what happens when CH2=COHCH2 reacts with hot concentrated KMNo4. i know the rupturing occurs on the double bond and oxygen is formed on the both sides of the ruptured double bond. there are 2 H on the right right so it changes into CO2+H2O. but what happens to the right side to the alcohol(OH). does it remains the same or changes. one question related to this
The compound hex-3-en-1-ol, P, has a strong ‘leafy’ smell of newly cut grass and is used in
perfumery.
CH3CH2CH=CHCH2CH2OH
P
What is produced when P is treated with an excess of hot concentrated acidic KMnO4?
A CH3CH2CH(OH)CH(OH)CH2CH2OH
B CH3CH2CH=CHCH2CO2H
C CH3CH2CHO and OCHCH2CH2OH
D CH3CH2CO2H and HO2CCH2CO2H