Author Topic: ALL CIE PHYSICS DOUBTS HERE !!!  (Read 171968 times)

Offline ashish

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #330 on: November 14, 2010, 04:04:28 am »
may/june 2009
20/21

I dont get it :(

no.20

young modulus will be constant in the same material
Y=young modulus=Stress/strain

Y=Fl/eA
Yp=Fpl/eA

YQ=FQ2l/e(A/2)
                   = 4FQl/eA

YQ=Yp
4FQl/eA=Fpl/eA
eliminating l,e and A
you will get

4FQ= Fp
Fp/Q= 4/1

Offline ashish

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #331 on: November 14, 2010, 04:22:24 am »
wrong questions.

http://www.xtremepapers.net/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_w09_qp_11.pdf


Q15

1st by law of conservation of momentum
m1v1=M2v2
2*2=1*v2
v2=4

kinetic energy of the two trolley = (0.5*2*22)+ 0.5*16
                                   =4+8
                                    =12

Offline ashish

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #332 on: November 14, 2010, 04:31:32 am »
may/june 2009
20/21

I dont get it :(

21) divide the graph into 2 trapeziums(0-20)and (20-30)

=((0.5*(20+10)*5)+ (0.5*(5+17)*10))/100
=1.85 + almost 6 squares out of the graph
=1.91
~ 2.0 A(approximation)


Offline ashish

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #333 on: November 14, 2010, 04:55:43 am »
S08 Q 24, 29, 32, 34 please
:)

24) directly C because for same materials young modulus is constant

32)
P=I2R
Px=I2R
R=Px/I2

Py= (I/2)22R
Py=I2R/2
R=2Py/I2

equating both you will get
Px=2Py

Py/Px= 1/2



34)rho will be constant in both wire

V=Ay*4L
V=Ax*L

equating both you will get
Ax =4Ay------(1)

R= (rho)L/A
rho=RA/L

for wire x
rho= Rx * Ax / L

for wire Y

rho = Ry * Ay /4L

equating both

Ry * Ay /4L = Rx * Ax / L

from 1 Ax =4Ay

now substitute in the equation

AyRy/4L = 4 AyRx/L

after simplifying
Ry=16Rx
Ry/Rx=16

Offline $!$RatJumper$!$

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #334 on: November 14, 2010, 07:42:37 am »
24) directly C because for same materials young modulus is constant

32)
P=I2R
Px=I2R
R=Px/I2

Py= (I/2)22R
Py=I2R/2
R=2Py/I2

equating both you will get
Px=2Py

Py/Px= 1/2



34)rho will be constant in both wire

V=Ay*4L
V=Ax*L

equating both you will get
Ax =4Ay------(1)

R= (rho)L/A
rho=RA/L

for wire x
rho= Rx * Ax / L

for wire Y

rho = Ry * Ay /4L

equating both

Ry * Ay /4L = Rx * Ax / L

from 1 Ax =4Ay

now substitute in the equation

AyRy/4L = 4 AyRx/L

after simplifying
Ry=16Rx
Ry/Rx=16

Thank you :)

Though could you please explain Q24 in terms of E = pL/Ae ? Like for instance by doubling L wouldn't we double E because they are proportional in the equation?
I get that the modulus doesn't change, but in terms of doubling and stuff, could you please explain :)

Offline birchy33

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #335 on: November 14, 2010, 08:35:54 am »
40 The following particles are each accelerated from rest through the same potential difference.
 
Which one completes the acceleration with the greatest momentum?
A ?-particle 
B electron 
C neutron 
D proton 

please explain. Its from ON07 QP1

Offline Hypernova

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #336 on: November 14, 2010, 09:03:51 am »
40 The following particles are each accelerated from rest through the same potential difference.
 
Which one completes the acceleration with the greatest momentum?
A ?-particle 
B electron 
C neutron 
D proton 

please explain. Its from ON07 QP1


All these particles will be accelarated in the same potential difference

the alpha particle has a charge of +2, the elecctron -1, the neutron 0 and the proton +1.

The Alpha particle will have the greatest force acting on it
Then the electron, then the proton.


Momentum = mass x velocity

Immediatelty ignore the neutron and electron. The neurton will not accelerate because it has no charge, so no velocity. The electron has negligble mass, so negligble momentum.


F=ma

Compare the proton and The Alpha particle

Proton has a force of 1 and The Alpha particle has a force of 2 on them, relative to each other

The mass of the proton is 1 and the mass of The Alpha particle is 4, relative to each other.

acceleration of the proton is 1 and the acc of The Alpha particle is 0.5

NOw we know that the velocity of the proton will increase faster than The Alpha particle

The both start from rest so using V=u+at, velocity = the acceleration x time



Momentum of the alpha particle = 4 x 0.5t = 2t
Momentum of the proton = 1 x 1t = t


Relative to each other, the momentum of the alpha particle increases by twice the momentum of the proton in 1 second.


This is a quantitative way of looking at it. But in the exam, I knew that the velocity of the alpha particle was only slightly smaller than the proton, and the alpha particle had 4 times the mass of the proton. I could confidently guess that the alpha particle would have the higher momentum.
Ya Allah! Make useful for me what You taught me and teach me knowledge that will be useful to me.

Offline birchy33

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #337 on: November 14, 2010, 09:14:34 am »
wow, thankyou! + rep

Offline TJ-56

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #338 on: November 14, 2010, 09:15:02 am »
Can you help me with the following p1 MCQs;

S03 Q20

S04 Q25

W05 Q34

Thankx for the help in advance!

Can anyone help me with those pls  ???

Offline Hypernova

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #339 on: November 14, 2010, 09:24:13 am »
W08 P1 Q 10, 27, 31, 36, 37 please :)

Sorry for all my questions! :(
S08 q29

Use the formula  lamda= fringe spacing X split spacing
                                      Distance of slits from screen

7x10-9 = 3x10-3 x split
                D

3.5x10-9 = ? x 2split
                  D


make things a bit neater


7x10-9 = 3x10-3 x K

3.5x10-9 = ? x 2k


sub in the 2 Ks


3.5x10-9 = ? x 2 (7x10-9 / 3x10-3)


solve to get ? = 0.00075 m

So ans is A
« Last Edit: November 14, 2010, 09:36:31 am by Hypernova »
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Offline Deadly_king

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #340 on: November 14, 2010, 09:47:58 am »
Can anyone help me with those pls  ???

Nov 05 No 34

Use the formula V = IR. Make R the subject of formula ---> R = V/I

Hence smallest resistance will result when V is minimum while I is maximum.

Therefore answer is C

Jun 04 No 25

At the instant the point Q is at a maximum which means it is temporarily stationary and it is neither moving upwards nor downwards.

At the same instant the point P is a zero displacement but is moving downwards since it was previously at Q and is moving downwards upto the minimum. ;)

Answer is A

Jun 03 No 20

Decreasing pressure by 10% ----> New pressure 0.1Po

Hence 0.1Po = heg

H becomes 0.1Po/eg which is equal to Po/10eg

Answer is A

Hope it helps :)

Offline TJ-56

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #341 on: November 14, 2010, 10:04:12 am »
Nov 05 No 34

Use the formula V = IR. Make R the subject of formula ---> R = V/I

Hence smallest resistance will result when V is minimum while I is maximum.

Therefore answer is C

Jun 04 No 25

At the instant the point Q is at a maximum which means it is temporarily stationary and it is neither moving upwards nor downwards.

At the same instant the point P is a zero displacement but is moving downwards since it was previously at Q and is moving downwards upto the minimum. ;)

Answer is A

Jun 03 No 20

Decreasing pressure by 10% ----> New pressure 0.1Po

Hence 0.1Po = heg

H becomes 0.1Po/eg which is equal to Po/10eg

Answer is A

Hope it helps :)

Thank you so much +rep
Just a question though

Jun 03 No 20
The child reduced p0 BY 10% and not TO 10%, isnt it supposed to be 0.9p0 rather than 0.1p0 , he reduced it BY 10%, so 90% is the new percentage, i understood this question once, but now it seems real confusing

and q34
Resistance = v/I
which is 1/gradient
So the greater the gradient, the lower the resistance, at B the gradient is greater than at C, so why cant B be the correct response?
Sorry for the questions, but i just need to get those clarified,
thank you

Offline Dania

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #342 on: November 14, 2010, 10:14:04 am »
Why is the answer B?
:)

Offline $!$RatJumper$!$

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #343 on: November 14, 2010, 10:16:09 am »
W07 Q 3, 6, 16, 22, 25, 37 :) thank you

Offline $!$RatJumper$!$

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #344 on: November 14, 2010, 10:19:19 am »
Why is the answer B?

Momentum before = Momentum after

Momentum before: (1000 + 10) * 0 = 0    ---> There was no initial velocity thus * 0

Momentum after: (1000 * 5) + (-10 * v) = 0    ---> Cannon ball moving in opposite direction so since it is velecity we need to specify its direction

Thus v = 500 ms-1

« Last Edit: November 14, 2010, 10:24:12 am by $!$RatJumper$!$ »