Can someone please explain me nov.2008 q3,39 
i need help in these questions urgently 
I can't get them at all I would really appreciate any help.....thanx
3. Only one electron in s-orbital -----> should be a group I metal.
So everyone apart
D is rejected.
Li is a Group I metal. So it has its outermost electron in an s-orbital. Cr is a transition metal. One of its s-orbital goes into it's partially filled d-orbital for stability.
39. From the information given above, you can note that for methane which contains only one carbon atom, ethane with two carbon atoms can be obtained as product. In other words the number of carbon atoms double.
So for propane which contains 3 carbon atoms, the resulting product may contain maximum 6 carbon atoms with as reactants two radicals carrying 3 carbon atoms.
The third one indeed contains 6 carbon atoms. But if you break it to form two radicals, you'll find that you'll be getting two compounds one with 4 carbon atoms and the other with only two carbon atoms.
This cannot be since propane contains 3 carbon atoms. So both radicals should contain 3 carbon atoms as well.
Answer is
B.
