Thank u very much for ur reply as well as ur explanation. It is really helpful, but can u explain Q4(b)(iii), of the same year Nov. 2008? You have explained Q3 not Q4 and what is the formula of the tripeptide as shown in the markscheme?....I really do appreciate ur co-operation.
Oops ....... sorry for the confusion dude.
4(b)(iii)That will depend on the equation you wrote for part (b)(i).
Let's take it to be : C
8H
18 -----> 2C
2H
4 + C
4H
10Now you need to find the enthalpy change for this reaction.
Number of bonds to be broken in the reactant : 18C-H bonds and 7C-C bonds.
Total number of bonds to be formed in the products : 2C=C bonds + 8C-H bonds and 3C-C bonds + 10C-H bonds.
Use the values from the Data Booklet to find :
(i) Energy required for bond-breaking : 18(410) + 7(350) = 9830 KJ/mol
(ii) Energy given out for bond formation : 2(610) + 8(410) + 3(350) + 10(410) = 9650 KJ/mol
Standard enthalpy change of reaction : 9830 - 9650 = +180 KJ/mol
NOTE : Bond breaking is endothermic(+ve) while bond forming is exothermic(-ve).
Same method is applied whatever the equation you wrote in (b)(i).(iv)The conditions include a temperature of about 600
oC. Hence this suggests that the reaction is endothermic since heat must be supplied for the reaction to occur and this is confirmed by the entahlpy change obtained in (b)(iii).
7(b)The formula of the tripeptide can vary. This is why the marking scheme only mentioned 'correct tripeptide'. The product in the second picture I uploaded earlier is the right answer. Except that it is asking for displayed formula, so you need to elaborate on the bonds and replace all the R groups by H for the simplest tripeptide.