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ALL CIE CHEMISTRY DOUBTS HERE !!

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iluvme:

--- Quote from: SkyPilotage on May 01, 2011, 04:50:49 pm ---Q4 f) First of all cracking alkanes forms alkanes or alkenes, since Z is unsaturated then its an alkene CnH2n.
You found the molecular mass in ii) as 42 g so you can do it by trial and error or : 12n+(1)x(2n)=42 ---> 14n=42 ---> n=3 so its C3H6 (propene)
     g) whenever u show the monomer or a polymer, the molecule should be shown in the form of "ethene" so just show 2 molecules of propene (without double bond ofcourse) as the polymer....

Q5 f)ii)  solubility of water relates to hydrogen bonds... So the product must have formed hydrogen bonds with water...(usully from the hydroxyl group OH-)

--- End quote ---

Q5 It doesn't have to do anything with water being polar?  :-\

SkyPilotage:

--- Quote from: iluvme on May 01, 2011, 04:52:14 pm ---Q5 It doesn't have to do anything with water being polar?  :-\

--- End quote ---
Hydrogen bonds are types of permanent dipole-dipole forces which exists only if the molecule is polar!!!!! But a polar molecule may have Permanent dipole forces but no hydrogen bonds...So u must mention tht hydrogen bonds form!

iluvme:
+ Rep Thank You!!

Besides I've got more doubts,   :-[

November 2007 Paper 2
Q1 b, Q2 e, Q3 d, Q5 e and d

EMO123:
1 b)
covalent bond is due to the attraction between the nuclei and electrons and there is an attraction electrostatic forces

EMO123:
2 e)i)

460K is Al2Cl6
1150K is AlCl3

2 e)ii)
in the attachment

2 e)iii)
in the attachment

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