Qualification > Sciences
ALL CIE CHEMISTRY DOUBTS HERE !!
Vin:
--- Quote from: $H00t!N& $t@r on April 28, 2011, 09:15:14 pm ---I understand what you mean... they want us to find out the oxidation number for the element attached to sulphur and not sulphur itself, but I thought that the oxidation number for S is -2 cuz it's right below oxygen.. :-\ and for the second one, SO2, why did you find the oxidation number for sulphur and not oxygen, the way you did for the first one, H2S... the last one was pretty simple :)
--- End quote ---
Okay, S8 is the molecule for sulfur, and is written as S in chemical eqaution, in the atomic form right? Hence, S is 0.
Ok, we know the oxidation state of oxygen, O, which is -2.
So, S + O2 = 0
x + 2 (-2) = 0
x = -4
Cuz to find the oxidation no. for any atom X in a compound you're supposed to know the other as well.
iluvme:
November 2006,
Q4 f and g
Q5 f ii)
Thank You :)
EMO123:
--- Quote from: iluvme on May 01, 2011, 03:13:58 pm ---November 2006,
Q4 f and g
Q5 f ii)
Thank You :)
--- End quote ---
i am sory but can you tell us which paper
iluvme:
--- Quote from: EMO123 on May 01, 2011, 04:13:32 pm ---i am sory but can you tell us which paper
--- End quote ---
Oh sorry Paper 2
SkyPilotage:
--- Quote from: iluvme on May 01, 2011, 03:13:58 pm ---November 2006,
Q4 f and g
Q5 f ii)
Thank You :)
--- End quote ---
Q4 f) First of all cracking alkanes forms alkanes or alkenes, since Z is unsaturated then its an alkene CnH2n.
You found the molecular mass in ii) as 42 g so you can do it by trial and error or : 12n+(1)x(2n)=42 ---> 14n=42 ---> n=3 so its C3H6 (propene)
g) whenever u show the monomer or a polymer, the molecule should be shown in the form of "ethene" so just show 2 molecules of propene (without double bond ofcourse) as the polymer....
Q5 f)ii) solubility of water relates to hydrogen bonds... So the product must have formed hydrogen bonds with water...(usully from the hydroxyl group OH-)
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