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ALL CIE CHEMISTRY DOUBTS HERE !!

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elemis:
@ratjumper

For question 10


--- Quote from: Ari Ben Canaan on November 16, 2010, 09:45:05 am ---@CS

For the Second question :

 

Imagine there is 1 mole of N2O4 hence there must be 2 moles of NO2

Therefore the partial pressures of each gas are 1/3 (N2O4) and 2/3 for NO2

inputting these into the initial equation at the top gives 4/3



--- End quote ---

komailnaqvi:
Plz anyone explain N08 Q2 P1. Im having probs in these volume related ques and nothing else! Thanks.

elemis:

--- Quote from: komailnaqvi on November 18, 2010, 07:42:06 am ---Plz anyone explain N08 Q2 P1. Im having probs in these volume related ques and nothing else! Thanks.

--- End quote ---

CS2(g) + 3O2(g) -----> CO2(g) + 2SO2(g)

10 cm3 of CS2 was used along with 50cm3 of O2. From the above equation we can see that only 30 cm3 of O2 is needed.

Thus, 20 cm3 of O2 is in excess and will remain unreacted at the end.

Since only 10cm3 of CS2 was used it is the LIMITING AGENT. Hence, only 10cm3 of CO2 is produced along with 20cm3 of SO2.

Thus, 20 + 10 + 20 = 50cm3

Hence, answer must be C or D

However, when the acidic gases (SO2 and CO2) are passed through NaOH they will be absorbed leaving only the excess O2 behind.

Hence, after addition of NaOH only 20cm3 of gases are left.

ANSWER = C
 

komailnaqvi:
thanx so much.
N09 Q20

yasser37:

in June 10 paper 11
can someone explain questions 13 , 22 ,28 , and 29

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