Qualification > Sciences
ALL CIE CHEMISTRY DOUBTS HERE !!
$!$RatJumper$!$:
S06 Q 10, 12, 17, 21, 25
Thank you kindly :)
birchy33:
You guys have been terrific and I hate to bundle you with more questions ... but ;D
O/N 09 QP1 variant 2
Q20
Q23
Q27
and to my much embarrassment ... Q1: I know its either A or D but I've completely forgot how to pick which one.
Cheers brudas.
Master_Key:
--- Quote from: birchy33 on November 18, 2010, 01:04:56 am ---You guys have been terrific and I hate to bundle you with more questions ... but ;D
O/N 09 QP1 variant 2
Q20
Q23
Q27
and to my much embarrassment ... Q1: I know its either A or D but I've completely forgot how to pick which one.
Cheers brudas.
--- End quote ---
O/N 09 QP1 Variant 2.
Q1. Answer is D.
It is because 0.2 Moles of HC burn to give 35.4 g of CO2.
So, RFM of CO2=(12+(16*2)=44 g.
35.4/44 = 0.8
0.8 = 0.2
? = 1
0.8/0.2=4
This is the simplest method. We get 4 Carbon atoms in one molecule of HC.
Do the Same with Water and we will get 8 Hydrogen atoms.
So the formula is C4H8
Master_Key:
--- Quote from: birchy33 on November 18, 2010, 01:04:56 am ---You guys have been terrific and I hate to bundle you with more questions ... but ;D
O/N 09 QP1 variant 2
Q20
Q23
Q27
and to my much embarrassment ... Q1: I know its either A or D but I've completely forgot how to pick which one.
Cheers brudas.
--- End quote ---
O/N 09 QP1 Variant 2.
Q23. Answer is A.
The diagram shows 2 double bonds between C=C atoms. These are the bonds which are broken and Hydrogen or Bromine added. The C=O will not break. Both the double bonds break and form a single bond C-C. 2 Hydrogen atoms are bonded with two Carbon atoms. There are four carbon atoms so 4 Hydrogen atoms.
This gives to 2 moles of both substances as both exist as diatomic molecules.
elemis:
--- Quote from: $!$RatJumper$!$ on November 17, 2010, 09:37:05 pm ---S06 Q 10, 12, 17, 21, 25
Thank you kindly :)
--- End quote ---
Question 17
Chlorine displaces Iodine from the salt. So the Iodide anions lose electrons to chlorine i.e. they are oxidised.
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