IGCSE MATHS DOUBTS HERE !!!!

[SauD~]

No problem shona 
I will give you some "completing the square" method examples - Later

Now I gotta go take my bath 

annie zanks, if i want anything i would ask, now i will get A*

[Arthur Bon Zavi]

annie zanks, if i want anything i would ask, now i will get A*

One ?

[SauD~]

One ?

seven seven

[ahmed_eg]

IGCSE Edexcel Maths paper 4H code 4400
number 7
HELP!

[The Golden Girl =D]

a] 68/80 * 100 = 85 %

b] 72 -> 60
     x  -> 100

x = (72*100)/60 = 120 marks.

I hope I helped =]

[SauD~]

a] 68/80 * 100 = 85 %

b] 72 -> 60
     x  -> 100

x = (72*100)/60 = 120 marks.

I hope I helped =]

in brief way for part b)

72 = 60/100* x
so the 100 moves to right side
so it comes as 72*100 = 7200
7200 = 60*x
then,
7200/60 = x
120 = x
done

[SauD~]

A piece of cake question..

What is acute angle? 

Thanks,

[elemis]

A piece of cake question..

What is acute angle? 

Thanks,

Any angle less than 90 degrees.

[SauD~]

Any angle less than 90 degrees.

hmm, ok, but what if there is a question
"measure the acute angle if the diagram"
so which angle will we take when both are acute angle..

The question number is 18th..

[Vin]

Theres just one acute angle between the two lines you draw :/

[SauD~]

Theres just one acute angle between the two lines you draw :/

i am sorry, i got it before you helped me...

i make so many silly mistakes

Thanks anyways

[SauD~]

I need help in question number three, part 1.

http://xtremepapers.net/CIE/Cambridge%20IGCSE/0580%20-%20Mathematics/0580_w10_qp_41.pdf

I got this paper in mocks, i did it correct but i forgot how i did

It is x * (72x - 2x) ---> i forgot how i found this

Thanks

[$tyli$h Executive]

I need help in question number three, part 1.

http://xtremepapers.net/CIE/Cambridge%20IGCSE/0580%20-%20Mathematics/0580_w10_qp_41.pdf

I got this paper in mocks, i did it correct but i forgot how i did

It is x * (72x - 2x) ---> i forgot how i found this

Thanks

The breadth of the rectangular enclosure is X.

Suppose the length is Y.

Total length of Fencing (given in question) = 72 metres. Thus total length of 3 sides = X + X+ Y=72 metres

Y = 72-2X

------------

Area = length X Breadth

=> X x Y

=> X x (72-2X)

=> 72X - 2X²

Done!

[SauD~]

The breadth of the rectangular enclosure is X.

Suppose the length is Y.

Total length of Fencing (given in question) = 72 metres. Thus total length of 3 sides = X + X+ Y=72 metres

Y = 72-2X

------------

Area = length X Breadth

=> X x Y

=> X x (72-2X)

=> 72X - 2X²

Done!

Thanks man
+rep

i now noticed that 72 meter is total perimeter -.-
i thought it was the length which you mentioned as Y.

Thanks

[$tyli$h Executive]

Thanks man
+rep

i now noticed that 72 meter is total perimeter -.-
i thought it was the length which you mentioned as Y.

Thanks

You're welcome!