S1 and S2 DOUBTS HERE!!!!

[immortal]

need help in June 09 number 1 , how to get Z....urgent

Which paper is this frm??

[simba]

nvm abt last one....I would like to know how to solve question 5 in Nov.09 first varient......urgently

[immortal]

I think this question waz already answered b4/

[immortal]

5a)
i>  no digits repeated range 5000-6000
      so 5xxx r da possibilities, 1,2,3,4,5,6    5 cannot b used
     remaining ones 5P3 as arrangement matters 4 numbers.

ii> repeated digits   all num frm 1-6 cn b used
         5xxx     so  5(6c1)(6c1)(6c1)
        so 6*6*6 num cn b formed dat is 6³

[simba]

mmmmm...another question in  Nov.09 first varient num.3..

[immortal]

5b)
i>  mor girls dan boys
   so   3g   2b
         4g   2b
         5g   0b

8c3*6c2+8c4*6c2+8c5
=1316

ii>Total of 8+6=14 students  11 if cousins r ignored.
   with cousins  11C2(wit 3 cousins already included)
   without dem   11C5
  so  55+462
       =517

[immortal]

mmmmm...another question in  Nov.09 first varient num.3..

Will ans in 15min

[immortal]

P(85 < x < 100)
                                         
           = 0.5 – P  [z < {(85 ? 100)/7}]           
                                                                   
                       
           = 0.5 – P (z < – 2.143)                     
           = 0.5 – (1 – ?(2.143))
           = 0.9839 – 0.5
           = 0.484       

[simba]

why is it times 0.5..

[simba]

another question in Nov.09 2nd varient num.1.....how to get standard  deviation

[Freaked12]

why is it times 0.5..

because its
100-100
---------
     7
which is zero

.The value of p corresponding to zero is 0.5

[Freaked12]

part two of Question 3 is also very easy
its states that 33 percent of times are the longest and smallest
so value of p of the middle is 0.34.

1-0.34=0.67
which is +-0.67
(a-100)/7=0.67

will give u the maximum time
(a-100)/7=-0.67
will give you the least time

[Freaked12]

i doubt anyone is awake
but if there is anyone on
answer the second variant of november 2009
question 4

[astarmathsandphysics]

Can you post the paper? My file is corrupted.

[Freaked12]

Can you post the paper? My file is corrupted.

Find how many different odd numbers greater then 500 can be made using some or all of the digits 1,3,5 and 6 with no digit being repeated

I did it but it took me half an hour to figure it out

But your output could proove to be valuable