Author Topic: S1 and S2 DOUBTS HERE!!!!  (Read 62624 times)

Offline ~ Miss Relina ~

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Re: S1 and S2 DOUBTS HERE!!!!
« Reply #285 on: November 24, 2011, 02:24:54 pm »
Yes and it will definitetely curve as nutters practice 168 hours a week and make less than zero mistakes

yes Thanks alot Sir  ;D
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silvercameron

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Re: S1 and S2 DOUBTS HERE!!!!
« Reply #286 on: November 25, 2011, 05:38:37 pm »
thankyou sir, i got how to do it.
But could you pls answer my other question?

Offline astarmathsandphysics

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silvercameron

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Re: S1 and S2 DOUBTS HERE!!!!
« Reply #288 on: November 26, 2011, 12:11:14 pm »
no sir. I am sorry but this isnt exactly my doubt. I wanted to know how we find the quartiles for large data with no classes.
For example:

Score          :     0       1         2       3       4      5      6
frequency :   36      94     48     15     7      3      1

Offline astarmathsandphysics

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Re: S1 and S2 DOUBTS HERE!!!!
« Reply #289 on: November 26, 2011, 10:21:15 pm »
For this one, there are 36+94+48+15+7+3+1=214
I would do this:214/4=53.5 so the lower quartile is 1
For the upper quartile find 3/4*215=160.5 so the upper quartile is 2
More complicated methods exist but for S1 do as above..

silvercameron

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Re: S1 and S2 DOUBTS HERE!!!!
« Reply #290 on: November 27, 2011, 03:25:40 pm »
thankyou,sir.oh, but my i already know about this method, but when solving some questions like this, i sometimes get the wrong answer.

Offline astarmathsandphysics

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Re: S1 and S2 DOUBTS HERE!!!!
« Reply #291 on: November 27, 2011, 11:23:32 pm »
Give examples. This method is for Edexcel.

silvercameron

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Re: S1 and S2 DOUBTS HERE!!!!
« Reply #292 on: December 01, 2011, 12:16:44 pm »
A question:
An ordinary dice was thrown 50 times and the resulting scores were summarised in a frequency table. The mean score was calculated to be 3.42. It was later found that the frequencies 12 and 9,of two consecutive scores,had been swapped. What is the correct value of the mean?

Offline astarmathsandphysics

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Re: S1 and S2 DOUBTS HERE!!!!
« Reply #293 on: December 01, 2011, 12:28:51 pm »
differene of12n+9(n-1)-12(n-1)-9n==12-9=3
3/50=0.06
3.42+0.06=3.48
or 3.42-0.06=3.36

Offline Sea Lover

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Re: S1 and S2 DOUBTS HERE!!!!
« Reply #294 on: December 07, 2011, 03:22:20 pm »
can somone help me with these two questions:
1-Three letters are selected at random from the word SCHOOL.Find the probablity that the selection:
a)does not contain the letter O
b)contains both letters O

2-In how many different ways can a football team of 11 players be photographed if there are to be two rows ,with 5 seated on the front row and 6 standing in the back row?In how many of these photographswould the captain be sitting in the centre of the front row?
thanx in adavnce

Offline astarmathsandphysics

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Re: S1 and S2 DOUBTS HERE!!!!
« Reply #295 on: December 07, 2011, 05:52:12 pm »
1a.4/6*3/5=12/30=2/5
b.2/6*1/5=1/15

2.11! cos each player is an individual and they can be told apart.
The captain can sit on the front in one of five places and the others can arrange themselves in 10! ways so5*10!

Offline ~ Miss Relina ~

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Re: S1 and S2 DOUBTS HERE!!!!
« Reply #296 on: December 08, 2011, 10:43:52 am »
1a.4/6*3/5=12/30=2/5
b.2/6*1/5=1/15

2.11! cos each player is an individual and they can be told apart.
The captain can sit on the front in one of five places and the others can arrange themselves in 10! ways so5*10!

Sir why how did you find the first answer ??? why did you mulitply 4/6 * 3/5 ...???
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Offline astarmathsandphysics

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Re: S1 and S2 DOUBTS HERE!!!!
« Reply #297 on: December 08, 2011, 10:57:01 am »
cos there are four non 'o' letters out of 6 so prob of not picking o is 4/6
when this letter is picked, there are three non 'o' letters out of five, so prob of picking non 'o' letter is 3/5
then 4/6*3/5

Offline astarmathsandphysics

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Re: S1 and S2 DOUBTS HERE!!!!
« Reply #298 on: December 08, 2011, 10:58:21 am »
theeducationchannel.info is working now. You can also ask for a 'video solution'

Offline ~ Miss Relina ~

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Re: S1 and S2 DOUBTS HERE!!!!
« Reply #299 on: December 08, 2011, 11:37:19 am »
cos there are four non 'o' letters out of 6 so prob of not picking o is 4/6
when this letter is picked, there are three non 'o' letters out of five, so prob of picking non 'o' letter is 3/5
then 4/6*3/5

but that's with assuming that the number is not replaced ......right ??? ok if that's the case then it might me 4/6*3/5*2/4 as he picked three numbers right ???

Thanks for the link I'll try it  ;)
~~~Yarab everything turns alright at the end ~~~
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