IGCSE MATHS Doubts

[bulono]

i use trial and error method....just play with the calculator to find the sequence.....if any1 knows any easy way please share....

[Vin]

Okay, I know what dependent events and independent events are, but where do we add and where do we multiply.

There is only one conclusion. There is no general hard-and-fast rule for probability. Sometimes you have to add, sometimes multiply, sometimes 1-(). It depends on the Question. And there is no explanation to why. So, basically, it's all screwed.

Addition is where there in no "Second Chance" lik pick up a coloured ball keep it back and pick another ball

Multiplication is where there is "more than one change" pick up a ball note colour pick up another ball (without replacing) note .. here the numerator and denominator of the second chance will decrease by one as u hav one ball in hand

Subraction is basically a "shortcut"  .. like 1-1/10 or something .. solve maj/june 2009 paper 4 prob. ques it has subtraction P.S there is always an alternative method to a subtraction   dont understand .. solve jun 2009

[bulono]

hello ,,it would be awsome  if anyone can show me the answer to october november 06 q 9 ..

thanks in advance .. wish every1 luck  

the 3 inequalities are y>=x so y-x>=0.....y+x<=12 as total time working is less than 12......x>=4 as he spends at least 4 hours cleaning cars

[ksitna]

suppose a sequence is
4, 12, 24, 40...........

how do u find the nth term?

u would use this method
a+(n-1)d+0.5(n-1)(n-2)c
4+(n-1)4+0.5(n-1)(n-2)4

and good l  luck simplifying

[SoONa]

the 3 inequalities are y>=x so y-x>=0.....y+x<=12 as total time working is less than 12......x>=4 as he spends at least 4 hours cleaning cars

hmm can u like take a screen shot of ur answer for the region and umm whts the answer for d 1 n 2 ... Thanks alottttt

[bulono]

whats the 8th term for 3,6,7,-2..... and also the formula......its question 9 from O/N 2007..

[Vin]

and in M/J 2005 Q 3 b how do i find the matrix....

another doubt M/J 2005 Q 2 c......

answered ??

[haris94]

u would use this method
a+(n-1)d+0.5(n-1)(n-2)c
4+(n-1)4+0.5(n-1)(n-2)4

and good l  luck simplifying

ummm im still not getting the right answer  
i got 2n²-2n+4

the answer is 2n²+2n

can u pls simplify and show me
thanx a million

[ksitna]

hmm can u like take a screen shot of ur answer for the region and umm whts the answer for d 1 n 2 ... Thanks alottttt

in d1 and 2
u nned the graph

u look at the points that are the least (4,4)
and the highest (6,6)
but first you have to make sure if it really is the highest and lowest
or u can solve it algebraically



VIN yes i think they are answered

[Vin]

ummm im still not getting the right answer  
i got 2n²-2n+4

the answer is 2n²+2n

can u pls simplify and show me
thanx a million

dude im getting the same .. =\

[Vin]

VIN yes i think they are answered

i see u;ve answered them ..

[haris94]

then i think the formula is wrong 

[bulono]

answered ??

yup....

[Vin]

then i think the formula is wrong 

number 'n' , common diff. 'd' , first term 'a' and difference change 'c'is:


a+d(n-1)+c/2(n-1)(n-2)

try this wat was the sequence By the way ??

[ksitna]

ummm im still not getting the right answer  
i got 2n²-2n+4

the answer is 2n²+2n

can u pls simplify and show me
thanx a million

okie
i hate simlifying so im sorry it took a while :/
i got the same thing as u so i must have done somat wrong but wait lemme check again.