Author Topic: Statastics 1 CIE Dout  (Read 682 times)

Offline joel

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Statastics 1 CIE Dout
« on: April 20, 2010, 05:16:46 pm »
Giving a brief explanation of your method, calculate the number of different ways in which the letters of the word TRIANGLES can be arranged if no two vowels may come together.

The answer is 151200.

This Question has been taken from Cambridge Advanced Level Mathematics Statistics 1 - Steve Dobbs and Jane Miller
Chapter 5 - Permutations and Combinations  miscellaneous exercise 5 question 8.

How do arrive at this answer?

Offline sweetie

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Re: Statastics 1 CIE Dout
« Reply #1 on: April 20, 2010, 06:10:12 pm »
6! * 7P3

6! - no. of wayz the consonants cud be arranged

7P3 - no. of wayz the 3 vowels cud be arranged

Offline joel

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Re: Statastics 1 CIE Dout
« Reply #2 on: April 20, 2010, 06:12:55 pm »
Thanks a lot

Offline sweetie

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Re: Statastics 1 CIE Dout
« Reply #3 on: April 20, 2010, 06:15:55 pm »
ur welcum ;D