1.It must factorise as (x-a)(x-b)(x-c) with a b and c all integers
Multiply this to givex^3-x^2(ab+bc+ac)+x(a+b+c)-216 (1)
If the smallest root is t then the other roots are rt and r^2t so product of roots r^3t^3=216
rt=6 so r=1,t=6 or r=6,t=1 or r=2,t=3 or some variation of these with plus or minus too.
I think a typo x^3-90x^2+bx-216=0 I get (x+3)(x+6)(x-12) b=-3
2.(-a+b)^3=-1 so -a+b=-1
(2a+b)^3=27 so 2a+b=3
a=4/3 b=1/3
will have to wait for q3