C1 & C2 Discussion here!

[omega007]

The answers for the trigonometric identities (part a) were:

For tan x part: -45 and 135

For sin x part: 23.6 and 156.4

    

Any other questions???

[onhsa]

So, everyone, did you fall for THE TRICK?Well, we all know how "easy" 4sinx=3tanx was. But what of the hidden agenda Edexcel so kindly cooked up for us? The ones who think have gotten it "right" did this:

4sinx=3(sinx/cosx)
(4/3)(sinx)(cosx)=sinx
(4/3)(cosx)=1(sinx/sinx)
(4/3)(cosx)=1
cosx= 3/4
and they found values for x

however, we have missed out alot of the question... keep reading




4sinx=3(sinx/cosx)
4(sinxcosx)=3sinx
4(sinxcosx)-3sinx=0
sinx(4cosx-3)=0
sinx=0
& then find values for sinx=0 as well
cosx=3/4
find values of cosx

So we have missed a part of the question, please post what u've done here, cos  if no one's gotten it right fully, they may accept the incomplete version as a correct answer.

[motherheaven]

in c2 paper wat was anyone lograhtim question second part answer

[master786]

my friend got it the right way

[motherheaven]

what was the answer anyone remember

[motherheaven]

plzzz anyone tell

[master786]

8 and 1/8

[motherheaven]

how answer can be 8 . can u tell me that log 2x + log 2x = 2log 2x can be possible.can u plzz write down all the steps

[master786]

it wud becum log2x  X log2x

[motherheaven]

i m getting square root of 512

[motherheaven]

ok in c2 paper in trapezium rule question what was the answer overestimate or underestimate.plzzzz reply

[master786]

overestimate

[motherheaven]

thnxxx and in c1 paper there was one question of sketching graph in part b) we have drawn the graph what were we suppose to do in c) which was a very long equation.like (x-2)whole cube..................plzzz reply

[omega007]

Translate it in the x-direction +2 units.

[omega007]

@onhsa....how many marks may we lose for that?