thats interesting, i got a whole bunch of different answers
Potassium Iodide is a reducing agent which means it brings about the reduction of others but itself is oxidised so for example you can test for it, by adding potassium manganate which is an oxidising agent it will bring about the oxidation of potassium iodide and itself will be reduced.
Potassium Manganate - will change from purple to colourless it has been reduced
Potassium Iodide - will change from colourless to orange because it has been oxidised to Iodine
OR...
when potassium iodide is added to hydrogen peroxide and sulphuric acid
the products will be iodine,potassim sulphate and water
H2O2 + 2KL + H2SO4 --> I2 + K2SO4 + 2H2O
you can note that hydrogen peroxide has been reduced (loses oxygen) and potassium iodide has acted as the reducing agent where it has been oxidised..
2I- ---> I2
(Colouless) to (red-brown)
My mum is a chemical engineer so she helps me alot with those kinda stuff