Author Topic: Maths & Physics Help  (Read 11397 times)

Q80BOY

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Re: Maths & Physics Help
« Reply #30 on: November 26, 2009, 09:51:57 am »
cause its not used much (this thread) so any posts here are noticable .. thus the many random doubts .. naughty naughty members :P :P

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #31 on: November 26, 2009, 09:53:38 am »
Would be easier for me if all the maths and physics questions were in the same topics. Else I might not find them

Q80BOY

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Re: Maths & Physics Help
« Reply #32 on: November 26, 2009, 10:00:54 am »
heyy sir .. long time no see ;D

so like a similar topic (like this one) in every board?

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #33 on: November 26, 2009, 10:29:17 am »
Yes |I did create one but people  make their own topics. It matters not. They are easier to find on my mobile phone so I post to say I will answer when I get home then look for my last posts when I get home.

Offline Tumble Bug

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Re: Maths & Physics Help
« Reply #34 on: December 20, 2009, 12:47:04 pm »
please i need someone to urgently solve this question!!...integration:

the limits are 1 and 0...it is 

x.f(x)

and f(x)= 2(x+2)/5

nid404

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Re: Maths & Physics Help
« Reply #35 on: December 20, 2009, 02:26:09 pm »
fx--> 2x+4/5
i dunno how to use the integration sign

f integration (x)--->2x/5 dx + 4/5dx
                            x2/5 +4/5x
                         
sorry i made an error in the previous integration

but u still don't get the ans......i will try agn                         
  
« Last Edit: December 20, 2009, 02:46:04 pm by nid404 »

Offline Tumble Bug

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Re: Maths & Physics Help
« Reply #36 on: December 20, 2009, 02:31:14 pm »
fx--> 2x+4/5
i dunno how to use the integration sign

f integration (x)--->2x2/5X2 + 4/5x
                           ---> x2+4x/ 5
substitute upper and lower limits
& then subtract lower limit from upper limit

2(1)2+ 4(1)/ 5=6/5
2(0)2+ 4(0)/ 5= 0

6/5-0=6/5

I think this is how it is to be done
                         

the answer is 8/15

:( :S

Offline Tumble Bug

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Re: Maths & Physics Help
« Reply #37 on: December 20, 2009, 02:33:49 pm »
thank you waisay!!  :)

nid404

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Re: Maths & Physics Help
« Reply #38 on: December 20, 2009, 02:46:53 pm »
edited my post...but still not that ans

Offline Tumble Bug

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Re: Maths & Physics Help
« Reply #39 on: December 20, 2009, 04:12:57 pm »
edited my post...but still not that ans

nevermind lets just hope nuthin of the sort cumes in my test! :-X

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #40 on: December 20, 2009, 05:16:00 pm »

xf(x)= 2x(x+2)/5=2x^2/5+4x/5 integrate to get 2x^3/15+2x^2/5
then put limits in to get (2/15+2/5).0=8/15

nid404

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Re: Maths & Physics Help
« Reply #41 on: December 20, 2009, 06:00:08 pm »
but it's 2(x+2)/5 nd not 2x(x+2)/5

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #42 on: December 20, 2009, 07:38:49 pm »
It says x.f(x)

nid404

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Re: Maths & Physics Help
« Reply #43 on: December 21, 2009, 03:56:37 am »

Offline Tumble Bug

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Re: Maths & Physics Help
« Reply #44 on: December 21, 2009, 11:13:39 am »
xf(x)= 2x(x+2)/5=2x^2/5+4x/5 integrate to get 2x^3/15+2x^2/5
then put limits in to get (2/15+2/5).0=8/15

omg thank you so much dude!!!
:)  :D