Author Topic: Maths & Physics Help  (Read 11382 times)

Offline astarmathsandphysics

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Maths & Physics Help
« on: October 06, 2008, 11:06:45 am »
Post your GCSE questions here to get the answers back asap from someone with 3 maths/physics degrees.

nid404

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Re: Maths & Physics Help
« Reply #1 on: April 22, 2009, 07:14:10 am »
I tried starting a new topic but it's not working for me. Anyways plz help me
The second part of the question needs help.
Q.The air in a bicycle tyre has a volume of 1000cm3 and a pressure of 2.5 atmospheres. If the air is released ( at the same temperature) so its pressure is 1 atmosphere, what is the volume of the air?

This part needs help

A bicycle has a volume of 100cm3 and is now used to pump up the tyre. After 1 stroke of the pump, what is the presure in the tyre?

Thanks

Offline spookyjaransh

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Re: Maths & Physics Help
« Reply #2 on: November 03, 2009, 09:54:52 am »
the constant here is = (1000/2.5) =400.
there fore after 1 stroke the volume increases by 100 cm3, thus new volume = 1100.
but because the constant does not change, therefore, 1100/x = 400
=> x = 1100/400 = 2.75 atm.

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #3 on: November 03, 2009, 10:26:46 am »
How did I miss this question for so long

Offline ~~~~shreyapril~~~~

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Re: Maths & Physics Help
« Reply #4 on: November 03, 2009, 10:39:58 am »
hm..!!
i guess you did not notice it!!
u are too busy person rite??
Friendship is like peeing on yourself. Everyone can see it but only you get the warm feeling that it gives :D :P :)

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #5 on: November 03, 2009, 10:58:16 am »
v busy

Offline @d!_†oX!©

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Re: Maths & Physics Help
« Reply #6 on: November 03, 2009, 12:04:23 pm »
the constant here is = (1000/2.5) =400.
there fore after 1 stroke the volume increases by 100 cm3, thus new volume = 1100.
but because the constant does not change, therefore, 1100/x = 400
=> x = 1100/400 = 2.75 atm.
hey ansh!!!
u've done one thing wrong here....
according to the boyle's law constant = pressure*volume
so, k=1000*2.5 = 2500
thus,
p= k/v
=>p=2500/1100
=>p=2.27 atm

am i right sir???
AAL IZZ WELL!!! ;)

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #7 on: November 03, 2009, 12:16:27 pm »
You were supposed to work out the volume of the air I think when the pressure is reduced from 2.5 atm to 1.

Offline Ghost Of Highbury

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Re: Maths & Physics Help
« Reply #8 on: November 03, 2009, 12:17:28 pm »
is it 2500/2600 = 0.9?
divine intervention!

Offline @d!_†oX!©

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Re: Maths & Physics Help
« Reply #9 on: November 03, 2009, 12:18:03 pm »
that was the first part...i think nid said she wanted help in the second part...
AAL IZZ WELL!!! ;)

Offline @d!_†oX!©

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Re: Maths & Physics Help
« Reply #10 on: November 03, 2009, 12:18:28 pm »
is it 0.9?
u talking abt the first or second part??
AAL IZZ WELL!!! ;)

Offline Ghost Of Highbury

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Re: Maths & Physics Help
« Reply #11 on: November 03, 2009, 12:19:42 pm »
I tried starting a new topic but it's not working for me. Anyways plz help me
The second part of the question needs help.
Q.The air in a bicycle tyre has a volume of 1000cm3 and a pressure of 2.5 atmospheres. If the air is released ( at the same temperature) so its pressure is 1 atmosphere, what is the volume of the air?

This part needs help

A bicycle has a volume of 100cm3 and is now used to pump up the tyre. After 1 stroke of the pump, what is the presure in the tyre?

Thanks

its ritten the second part needs help.
divine intervention!

Offline spookyjaransh

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Re: Maths & Physics Help
« Reply #12 on: November 03, 2009, 12:24:55 pm »
so wats the correct answer then?? ???

Offline astarmathsandphysics

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Re: Maths & Physics Help
« Reply #13 on: November 03, 2009, 12:53:43 pm »
pV=k so 2.5*1000=k so V=2500/p but p is now 1atm so V=2500cm£

Some of the air escaped to the atmosphere

Offline @d!_†oX!©

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Re: Maths & Physics Help
« Reply #14 on: November 03, 2009, 12:55:39 pm »
sir cud u do the second part as well??
AAL IZZ WELL!!! ;)