i'm getting confused about the dibasic thing... i also divided by 2, my gradient came out to be 32.7.... which is double what the marking scheme says... and yeah... the reaction is as follows...
2NaOH + HOOC-R-COOH --> Na+-OOC-R-COO-Na+ + 2H2O
so number of moles of di ethyl ether would be 1/2 of number of moles of NaOH
have i got this all wrong or sumthing?? or is it an examiner's mistake