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how come the amplitude is times 2?
intensity= amplitude^2
No, there are two different constants, k1 and k2. The "2" is not multiplied by A, it belongs to the constant k. k1 and k2
8. XY - 40m - 12s XZ - 80m - 18s80 = 18u + 0.5a*18^240 = 12u + 0.5a*12^2Solve the simultaneous equations, by eliminating u and calculating a.9. There's a little bit of guess work involved here.Given it's inelastic, the rebound velocity won't be v. Say, 40% of energy is lost, say around 0.6vChange = (-0.6v*2m) - 2mv = -3.2mvSO the change is almost 3mv.(Even if u take 0.7v, u won't get 4mv+)15. Steady speed v, therefore weight is balanced by retarding forcemg = kvv = mg/kKE = 0.5mv^2 = 0.5m*(mg/k)^2 = m/2 * m^2g^2 /k^2 = m^3g^2 /2k^234. When x = 0, the voltage measured is across the whole of the wire, so it has to be V. when x decreases, and the pointer is moved at the right end of the part with resistivity p, the voltage is divided into 2 parts (p and 2p+3p) So the voltage across the length x is now, not V, but a lil less than V because some VOltage is lost in the remaining length of the wire.Answer: B (note the graph is not a straight line because as x decreases, the resistance doesn't decrease proportionately)---23. frequency = 1/(time taken for 1 complete oscillation = 50m (check x-axis))It covers 8m in 1 second (speed)so 50m in 50/8 s = 6.25That's its time periodHence, frequency = 1/t = 1/6.25 = 0.16HzSpeed = 2pi*a*f = 2pi*2*0.16 = 2.01m/sKE = 0.5mv^2 = 4mJ25. dsin45 = 3*lambdad = 3lambda/sin 45 = 3sqrt(2)*lambdamaximum order of diffraction = dsin90 = n*lambdan = d/lambdan = (3sqrt(2)*lambda)/lambda = 3sqrt(2) = 4.24264.... ~ 4
guysdo we have to learn the frequencies and wavelenghts of colrs of light?like red, yellow... etc.?
Can someone please help me out with q 37http://www.xtremepapers.me/CIE/International%20A%20And%20AS%20Level/9702%20-%20Physics/9702_s08_qp_1.pdf
WOW thanks man....ur good lolAALSO...I know that a electric field with the positive plate earthed will still have a positive chargeon it...but what if a theres an electric field and the NEGATIVE plate is earthed??? will there still be a negative charge on it??? or will there be no charge on it...??
COmbined resistance of VOltmeter and R2 = 50ohmsVOltage that part receives = 50/150 * 6 = 2VCurrent = V/R = 2/100000 = 20*10^-6
w03_qp1 Question 16Doubt : How is the force H at the hinge greater than the Weight?
