Author Topic: ALL CIE PHYSICS DOUBTS HERE !!!  (Read 151898 times)

Offline Vin

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #525 on: April 23, 2011, 04:57:02 pm »
hey can anyone answer this  ???
The amount of electrical energy transferred when a charge of 8 mC moves through a
potential difference of 12 V ??

Product of the two? convert mC to C

Offline Vin

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #526 on: April 23, 2011, 04:59:58 pm »
can anybody tell me a perfect definition of Stress and Strain

Strain's just when an object is extended by, for eg, delta L , right? Wonder how'd you define it.

Stress is F/A , so tensile force F acting normally to an area A, i suppose?

Offline EMO123

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #527 on: April 23, 2011, 05:08:18 pm »
Strain's just when an object is extended by, for eg, delta L , right? Wonder how'd you define it.

Stress is F/A , so tensile force F acting normally to an area A, i suppose?
thanx man

Offline $H00t!N& $t@r

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #528 on: April 24, 2011, 11:12:59 pm »
Q 18

4 MW is maximum is 80%.
Then 100% is 5 MW.

P = IV
5 X 106   = I X 25 X 103
I = 200 A


Q 25

Count the phase difference from X. 3 (Crest to trough) = 720 = 3 pie. n = 3.


Q 27

n X Lamda = d sin x

n = 1 (first order)
N = 500
d = 1/N
Lamda = d X sin x
              ------------
                    n

= (1/500) X Sin 30
= 1 X 10-3 m




Thanks a lot! +rep  :)
"If A equals success, then the formula is:
A=X+Y+Z, X is work. Y is play. Z is keep your mouth shut"- Albert Einstein

Offline $H00t!N& $t@r

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #529 on: April 25, 2011, 02:48:45 pm »
"If A equals success, then the formula is:
A=X+Y+Z, X is work. Y is play. Z is keep your mouth shut"- Albert Einstein

Offline astarmathsandphysics

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #530 on: April 25, 2011, 03:16:56 pm »
9)s=1/2at^2
10=1/2*10t^2 so t=sqrt(2)=1.43
v=u+at=0+9.8*1.43=14m/s
D

13.moments about pivot 1.5W=2.5*300=750
W=750/1.5=500
37)A current though 3 ohm resistor is twice the current though the 6 ohm resisitor but the current thought the 2 ohm resistors are the same.
total resistance of 3 &6 ohm branch is 2 ohms (1/3+1/6)^-1 =2 but total resistance of 2& 2 ohm branch os 1 (2+2)^-1 =1 so more volts need to drive cuurent through 3 & 6 ohm brach.

Offline $H00t!N& $t@r

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #531 on: April 25, 2011, 04:09:51 pm »
9)s=1/2at^2
10=1/2*10t^2 so t=sqrt(2)=1.43
v=u+at=0+9.8*1.43=14m/s
D

13.moments about pivot 1.5W=2.5*300=750
W=750/1.5=500
37)A current though 3 ohm resistor is twice the current though the 6 ohm resisitor but the current thought the 2 ohm resistors are the same.
total resistance of 3 &6 ohm branch is 2 ohms (1/3+1/6)^-1 =2 but total resistance of 2& 2 ohm branch os 1 (2+2)^-1 =1 so more volts need to drive cuurent through 3 & 6 ohm brach.

Thanks sir, but I don't understand your working for q13...  :-\  How is the answer 480N ?
"If A equals success, then the formula is:
A=X+Y+Z, X is work. Y is play. Z is keep your mouth shut"- Albert Einstein

Offline HUSH1994

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #532 on: April 25, 2011, 04:19:14 pm »
As the weight acts at the middle,and the beam is in equilibrium,you can make the following equation:
300*2 = 1.25X
X= 600/1.25 = 480N
1.25 is the middle of the beam,X is the weight and as the distance between the 300N force and the pivot is 2 m.

Hope you get it :)

Offline $H00t!N& $t@r

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #533 on: April 25, 2011, 04:33:07 pm »
As the weight acts at the middle,and the beam is in equilibrium,you can make the following equation:
300*2 = 1.25X
X= 600/1.25 = 480N
1.25 is the middle of the beam,X is the weight and as the distance between the 300N force and the pivot is 2 m.

Hope you get it :)

oh! thanks i get it  :)
"If A equals success, then the formula is:
A=X+Y+Z, X is work. Y is play. Z is keep your mouth shut"- Albert Einstein

Offline HUSH1994

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #534 on: April 25, 2011, 04:33:46 pm »
No problem :)

Offline Vin

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #535 on: April 25, 2011, 05:02:57 pm »
P1 Q27 ON 2002.
A wave of amplitude a has intensity of 3.0 Wm^-2
What is the intensity of a wave of the same frequency that has an amplitude 2a?
how come the answer is 12

Did you get Q36 from the same paper? I dont seem to get it :/

Offline HUSH1994

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #536 on: April 25, 2011, 05:39:19 pm »
each of the 3 resistors has 5 K(ohms),and the potential differnce across the circuit is 2 volts,so each resistor will get 2/3V(the six of them as they are connected in parallel)and the V at X is 4/3(as you have 2 resistors before)and 2/3 at Y,so 4/3 - 2/3 = 2/3.

Im not really good at explaining but i hope you get it

Offline EMO123

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #537 on: April 25, 2011, 06:24:36 pm »
each of the 3 resistors has 5 K(ohms),and the potential differnce across the circuit is 2 volts,so each resistor will get 2/3V(the six of them as they are connected in parallel)and the V at X is 4/3(as you have 2 resistors before)and 2/3 at Y,so 4/3 - 2/3 = 2/3.

Im not really good at explaining but i hope you get it
but still you explained the whole doubt

Offline Aadeez || Zafar

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #538 on: April 25, 2011, 06:41:12 pm »
hehehe



Yeh BaaabuRaao ka style hein!

Offline EMO123

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #539 on: April 26, 2011, 02:56:42 pm »