Author Topic: ALL CIE PHYSICS DOUBTS HERE !!!  (Read 151598 times)

Offline Deadly_king

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #240 on: November 11, 2010, 05:23:44 am »
What is this equation?? I've never heard about it. What is it used to calculate and when should we use it?

By the way, whats phi?

phi/2pi = AB/lambda

Thankx

It's the equation of phase difference (phi)

Phase difference = 2(pie)x / lambda

Take AB as x and phi as phase difference and you'll get the equation :
phi/2(pie) = AB/lambda  ;)

Offline $!$RatJumper$!$

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #241 on: November 11, 2010, 05:35:30 am »
It's the equation of phase difference (phi)

Phase difference = 2(pie)x / lambda

Take AB as x and phi as phase difference and you'll get the equation :
phi/2(pie) = AB/lambda  ;)

Makes sense. Thank you DK and TJ-56 :)

Offline $!$RatJumper$!$

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #242 on: November 11, 2010, 05:40:27 am »
5(a)
1. The waves should meet in antiphase at M. ( phase difference = pie)
2. Sources must emit waves having same amplitude.

(b)
So the wavelength ranges from 330/4000  to 330/1000 (v/f) which is 8.25 to 33 cm
The distance from S2 to M is 128 (root(100sqr +80sqr))
So the phase difference is 128-100 which is 28
using the equation
phi/2pi = AB/lambda
as phi must be pi rad, 1/2 = AB/lambda
AB= 28
so making lambda the subject: lambda= (28*2)/n , where n could be 1,3,5,7 (to be out of phase)
so trying out 1,3,5,7 give us 56, 18.7, 11.2, and 8 respectively, as 18.7 and 11.2 are the only 2 values inside the range i calculated at the beginning, then the number is 2
hope that was helpful


One other thing i dont get. Where did n suddenly come into this equation from? And how can we take the phase diff to be pie. We dont know if they are completely out of phase. Yes they are out of phase by 28m, but doesnt pie rad mean they are completely out of phase by exactly half a wavelength?

Offline Deadly_king

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #243 on: November 11, 2010, 05:42:37 am »
Thanx for the answer +rep
But can u explain further part 1 of the question
thanx in advance


1. From the equation you can note that mass is conserved.

Total initial mass : 18 and total final mass : 18 -----> ( Add the mass numbers of the different elements and particles taking part in the reaction )

Now you're asked how Energy is conserved.
Energy emitted = delta(m) x c2 = 1.1 MeV

Therefore for total energy to be conserved,
Mass energy of products + energy emitted = Initial mass energy of reactants.

The energy emitted is released in the form of kinetic energy of the alpha-particle. ;)

Hope you understand :)
« Last Edit: November 11, 2010, 09:45:18 am by Deadly_king »

Offline Deadly_king

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #244 on: November 11, 2010, 05:49:57 am »
One other thing i dont get. Where did n suddenly come into this equation from? And how can we take the phase diff to be pie. We dont know if they are completely out of phase. Yes they are out of phase by 28m, but doesnt pie rad mean they are completely out of phase by exactly half a wavelength?

It is said that the microphone M detects maxima and minima of intensity of sound.

Maxima and Minima takes place only when the two waves meet in anti-phase. ;)

The n indicates the number of wavelengths at which the two waves will meet. It may be any number, but in this case since it is in anti-phase it has to be an odd number.

Phase difference = 2(pie)x / lambda is used to find the phase difference between two consecutive points only,i.e the two pints are less than one wavelength apart.

Offline $!$RatJumper$!$

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #245 on: November 11, 2010, 05:57:02 am »
It is said that the microphone M detects maxima and minima of intensity of sound.

Maxima and Minima takes place only when the two waves meet in anti-phase. ;)

The n indicates the number of wavelengths at which the two waves will meet. It may be any number, but in this case since it is in anti-phase it has to be an odd number.

Phase difference = 2(pie)x / lambda is used to find the phase difference between two consecutive points only,i.e the two pints are less than one wavelength apart.

ok i get the rad part. But for the n part, isnt it meant to be n+1/2 ? why do you say it should be an odd number?

Offline Deadly_king

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #246 on: November 11, 2010, 06:01:21 am »
ok i get the rad part. But for the n part, isnt it meant to be n+1/2 ? why do you say it should be an odd number?

That's right. :D

When it is (n+1)/2, it usually is an odd number. ;)

Offline birchy33

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #247 on: November 11, 2010, 06:03:45 am »
HELP! How do you figure out questions where they ask for the distance between molecules and all that sort of stuff. Like the distance between solid and liquid?

Offline TJ-56

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #248 on: November 11, 2010, 07:20:30 am »
1. Form the equation you can note that mass is conserved.

Total initial mass : 18 and total final mass : 18 -----> ( Add the mass numbers of the different elements and particles taking part in the reaction )

Now you're asked how Energy is conserved.
Energy emitted = delta(m) x c2 = 1.1 MeV

Therefore for total energy to be conserved,
Mass energy of products + energy emitted = Initial mass energy of reactants.

The energy emitted is released in the form of kinetic energy of the alpha-particle. ;)

Hope you understand :)

Oh ok.
Thanks alot dk.

Offline TJ-56

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #249 on: November 11, 2010, 09:21:45 am »
HELP! How do you figure out questions where they ask for the distance between molecules and all that sort of stuff. Like the distance between solid and liquid?

Well the distance between solid particles and liquid particles are quite similar, but its rather the movement of those particles that differ the most. In gases, the separation of particles are much greater than that of solids and liquids (approximately 10 molecular diameters).
Hope that was helpful and covered your question completely.

Offline $!$RatJumper$!$

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #250 on: November 11, 2010, 09:28:41 am »
That's right. :D

When it is (n+1)/2, it usually is an odd number. ;)

haha no i mean (n+1/2)lambda

Offline birchy33

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #251 on: November 11, 2010, 09:34:01 am »
Well the distance between solid particles and liquid particles are quite similar, but its rather the movement of those particles that differ the most. In gases, the separation of particles are much greater than that of solids and liquids (approximately 10 molecular diameters).
Hope that was helpful and covered your question completely.


Hmm I mean in like when you are asked to find the distance between molecules or the RATIO between distance between molecules in a solid compared to  a liquid or gas.

Offline astarmathsandphysics

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #252 on: November 11, 2010, 09:45:11 am »
the ratio is cube root(density of solid/density of gas)

Offline Deadly_king

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #253 on: November 11, 2010, 09:48:45 am »

Oh ok.
Thanks alot dk.


Anytime buddy :)

haha no i mean (n+1/2)lambda

Oops.........i mistyped it.

The equation is (2n + 1)/2 or n + 1/2.

This equation is only used when the waves meet in anti-phase, i.e there will be maximum destructive interference.
« Last Edit: November 11, 2010, 09:52:02 am by Deadly_king »

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Re: ALL CIE PHYSICS DOUBTS HERE !!!
« Reply #254 on: November 11, 2010, 10:15:49 am »
Alright that makes sense now :) thankx

Ok can you please have a look at S10 P21 Q4b

So, i use y = (D*lambda) / d to find d. Then I did 1 / d to find the answer. I got it right, but then looked at the MS and saw they used d*sin(theta) = n*lambda to find d. Then they did 1 / d to get the answer.

What im confused about is that when are we meant to know what formula to use where?