1st v solve by pythagoras rule...to find the distance between the apple trees..
x=root of<5
2-3
2>
x=4
*by 2 cz notice v calculated half the distance....therefore...total distance between each apple tree=8
then 400/8=50...n den v add 1..50+1=51 <since for 50 parts the trees r on both sides whch = 51>
Apple trees=51
Cheery trees = 50
<this is bcz in each part there is only 1 cherry tree<in middle of two apple trees>,,therefore,,50 parts,,50 cherry trees>
hope this helps