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Author Topic: IGCSE MATHS DOUBTS HERE !!!!  (Read 34726 times)

elemis

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Re: IGCSE MATHS DOUBTS HERE !!!!
« Reply #15 on: September 17, 2010, 07:01:32 am »
Quote from: Kimo Jesus on September 17, 2010, 06:59:07 am
yea why?

What is the answer at the back say and which textbook are you using ?
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Re: IGCSE MATHS DOUBTS HERE !!!!
« Reply #16 on: September 17, 2010, 07:05:44 am »
Quote from: Ari Ben Canaan on September 17, 2010, 07:01:32 am
What is the answer at the back say and which textbook are you using ?
its says 32.6 but i made some errors while calculating so , thats why i said 33.2 anyway

beliefe it or not my front cover is cut off so i cant see the name at all but i think its DAVID RAYNER IGCSE FOR MATHEMATICS
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elemis

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Re: IGCSE MATHS DOUBTS HERE !!!!
« Reply #17 on: September 17, 2010, 07:07:13 am »
which page no. ?
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Re: IGCSE MATHS DOUBTS HERE !!!!
« Reply #18 on: September 17, 2010, 07:12:05 am »
205 question 9

youll be very kind if you do question 11 for me
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elemis

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Re: IGCSE MATHS DOUBTS HERE !!!!
« Reply #19 on: September 17, 2010, 07:18:45 am »
Part (a)
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elemis

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Re: IGCSE MATHS DOUBTS HERE !!!!
« Reply #20 on: September 17, 2010, 07:21:40 am »
Quote from: Kimo Jesus on September 17, 2010, 07:05:44 am
its says 32.6 but i made some errors while calculating so , thats why i said 33.2 anyway

beliefe it or not my front cover is cut off so i cant see the name at all but i think its DAVID RAYNER IGCSE FOR MATHEMATICS

I know why I got it wrong. You see in your diagram you wrote 7 m in between those two lines. I thought 7m was the length of the staright one.

See diagram.
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Re: IGCSE MATHS DOUBTS HERE !!!!
« Reply #21 on: September 17, 2010, 07:25:18 am »
Quote from: Ari Ben Canaan on September 17, 2010, 07:21:40 am
I know why I got it wrong. You see in your diagram you wrote 7 m in between those two lines. I thought 7m was the length of the staright one.

See diagram.
oh lol :P my bad :P wasted your time :P

anyway can you do question 11 if ur free?
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NO secrets to SUCCESS , it is the result of 1.HARD WORK 2.GOOD PREPARATION 3.LEARNING FROM FAILURE
But it ain't how hard you hit; it's about how hard you can get hit, and keep moving forward-Balboa

elemis

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Re: IGCSE MATHS DOUBTS HERE !!!!
« Reply #22 on: September 17, 2010, 07:26:01 am »
Quote from: Kimo Jesus on September 17, 2010, 07:25:18 am
oh lol :P my bad :P wasted your time :P

anyway can you do question 11 if ur free?

See post no.19 for part a.

I'm doing b now.
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elemis

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Re: IGCSE MATHS DOUBTS HERE !!!!
« Reply #23 on: September 17, 2010, 07:31:41 am »
Part (b) Question 11

See pic.
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Re: IGCSE MATHS DOUBTS HERE !!!!
« Reply #24 on: September 17, 2010, 07:34:08 am »
Quote from: Ari Ben Canaan on September 17, 2010, 07:31:41 am
Part (b) Question 11

See pic.

oh Thanks !.That was easy , its just that i cant put the words into a diagram :/ Thanks alot!
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NO secrets to SUCCESS , it is the result of 1.HARD WORK 2.GOOD PREPARATION 3.LEARNING FROM FAILURE
But it ain't how hard you hit; it's about how hard you can get hit, and keep moving forward-Balboa

elemis

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Re: IGCSE MATHS DOUBTS HERE !!!!
« Reply #25 on: September 17, 2010, 07:37:55 am »
Quote from: Kimo Jesus on September 17, 2010, 07:34:08 am
oh Thanks !.That was easy , its just that i cant put the words into a diagram :/ Thanks alot!

Practice makes perfect ;)

No worries :)
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Re: IGCSE MATHS DOUBTS HERE !!!!
« Reply #26 on: September 17, 2010, 04:07:08 pm »
ARI

PAGE 196 , QUESTION 8 , (C)

thanks in advanced

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elemis

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Re: IGCSE MATHS DOUBTS HERE !!!!
« Reply #27 on: September 17, 2010, 04:13:10 pm »
(a) Since tan x = Opposite/Adjacent

Hence, tan 25 = h / length OA

Re-arranging we get h / tan25 = length OA

(b) Same idea as above :  tan 33 = h / length OB  

Re-arranging give  Length OB = h/ tan33

Give me some time for (c)
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Re: IGCSE MATHS DOUBTS HERE !!!!
« Reply #28 on: September 17, 2010, 04:17:29 pm »
Quote from: Ari Ben Canaan on September 17, 2010, 04:13:10 pm
(a) Since tan x = Opposite/Adjacent

Hence, tan 25 = h / length OA

Re-arranging we get h / tan25 = length OA

(b) Same idea as above :  tan 33 = h / length OB  

Re-arranging give  Length OB = h/ tan33

Give me some time for (c)

tyt
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NO secrets to SUCCESS , it is the result of 1.HARD WORK 2.GOOD PREPARATION 3.LEARNING FROM FAILURE
But it ain't how hard you hit; it's about how hard you can get hit, and keep moving forward-Balboa

elemis

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Re: IGCSE MATHS DOUBTS HERE !!!!
« Reply #29 on: September 17, 2010, 04:23:34 pm »
Look carefully at triangle ABO. It is a right angle triangle. Hence, using Pythagoras's Theorem :

60^2 = (\frac{h}{tan25})^2 + (\frac{h}{tan33})^2


3600 = \frac{h^2}{0.217443} + \frac{h^2}{0.4217302}


3600 = \frac{ 0.217443h^2+0.4217302h^2}{0.217443*0.4217302}


3600 = \frac{ 0.639173222h^2}{0.091702213}


3600 * 0.091702213=0.639173222h^2


330.1279699 =0.629173222 h^2


Solving this gives h = 22.7 m
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