IGCSE/GCSE/O & A Level/IB/University Student Forum

Qualification => Subject Doubts => GCE AS & A2 Level => Sciences => Topic started by: Twinkle Charms on June 07, 2010, 07:16:49 pm

Title: phy p2 doubts =\
Post by: Twinkle Charms on June 07, 2010, 07:16:49 pm
M/J07 Q3 c(ii)

paper is attached.
Title: Re: phy p2 doubts =\
Post by: Twinkle Charms on June 07, 2010, 07:41:03 pm
also in Q4 a(ii) [same paper attached] why do we add the P.E. and K.E here? they asked total kinetic energy so umm whats potential energy doing? =\
Title: Re: phy p2 doubts =\
Post by: vserian on June 07, 2010, 08:29:26 pm
potential energy is converted into KE when it falls down.
since there is a KE at the top ther will be anothe KE when it reach the sea and that KE is equal to the PE
so total is KE plus PE
Title: Re: phy p2 doubts =\
Post by: Twinkle Charms on June 07, 2010, 10:57:30 pm
aite thx vserian

so Q3 still unanswered =\

in same paper M/J07 Q4d(i) and (ii)


O/N07 Q1 b , how to calculate the uncertainty, im gettin 6.9*10^-3 whereas in ms it says 0.009 ..??

this paper is attached to the post..
Title: Re: phy p2 doubts =\
Post by: astarmathsandphysics on June 07, 2010, 11:15:11 pm
3a)density=mass/volume
bi)mass=Ahp
bii)pressure=force/area=mg/A=Ahpg/A=hpg
ci)volume=mass/density so if masses are the same, colume of water vapour/volume of water=1/(1/1600)=1600
ii)cube root(1600)=11.7 remeber that volume =l^3 so l=cube root of volume
di)they have the same density
ii|)high melting point
iii)cannot deform easily, unlike liquids
Title: Re: phy p2 doubts =\
Post by: Twinkle Charms on June 07, 2010, 11:20:17 pm
3a)density=mass/volume
bi)mass=Ahp
bii)pressure=force/area=mg/A=Ahpg/A=hpg
ci)volume=mass/density so if masses are the same, colume of water vapour/volume of water=1/(1/1600)=1600
ii)cube root(1600)=11.7 remeber that volume =l^3 so l=cube root of volume
di)they have the same density
ii|)high melting point
iii)cannot deform easily, unlike liquids
Thanks astar, explain other ques also please..
Title: Re: phy p2 doubts =\
Post by: Twinkle Charms on June 07, 2010, 11:29:23 pm
Q2 d (ii) in O/N07,  why do we add the forces 75 and 23 and why not subtract ???
Title: Re: phy p2 doubts =\
Post by: astarmathsandphysics on June 07, 2010, 11:33:33 pm
jun07 di) draw a vector 18 to the right and sqrt(25^2-18^2)=17.3 down
ii)tan^(-1(17,3/18))=44 degrees
Title: Re: phy p2 doubts =\
Post by: falafail on June 07, 2010, 11:34:24 pm
aite thx vserian

so Q3 still unanswered =\

in same paper M/J07 Q4d(i) and (ii)


O/N07 Q1 b , how to calculate the uncertainty, im gettin 6.9*10^-3 whereas in ms it says 0.009 ..??

this paper is attached to the post..

i think this is how its done:

make R the subject of the formula, you get R=(V/pi X L)^1/2
to calculate the uncertainty here, you need to find the percentage uncertainty first then multiply by the value you get for R
in this case, % uncertainty in R = 1/2(% uncertainty in V + % uncertainty in L)
which is 0.019
the value you get for R is approximately 0.4886
so uncertainty = 0.4886 X 0.019 = 0.009
Title: Re: phy p2 doubts =\
Post by: astarmathsandphysics on June 07, 2010, 11:37:23 pm
Q2 d (ii) in O/N07,  why do we add the forces 75 and 23 and why not subtract
I dont understand your question
use P=Fv=23*4.5=103.5W
Title: Re: phy p2 doubts =\
Post by: astarmathsandphysics on June 07, 2010, 11:38:39 pm
thanks for doing the uncertainty question. Cat being overaffectionate at the mo
Title: Re: phy p2 doubts =\
Post by: Twinkle Charms on June 08, 2010, 12:05:30 am
thanks to both =)
Title: Re: phy p2 doubts =\
Post by: Twinkle Charms on June 08, 2010, 12:13:58 am
Q2 d (ii) in O/N07,  why do we add the forces 75 and 23 and why not subtract
I dont understand your question
use P=Fv=23*4.5=103.5W
thats rong, ull be awarded only 1 mark out of 2.

in mark scheme they added both the forces and then used in this eqtn p=fv, why?
F=75N is taken from the previous sub question's answer.