IGCSE/GCSE/O & A Level/IB/University Student Forum

Qualification => Subject Doubts => GCE AS & A2 Level => Sciences => Topic started by: superduper2009 on May 15, 2010, 04:37:57 pm

Title: physics base units
Post by: superduper2009 on May 15, 2010, 04:37:57 pm

can someone explain how to express voltage in base units ... thanks :D

Title: Re: physics base units
Post by: [Spy] on May 15, 2010, 04:45:09 pm

P=IV
therefore
V=P/I
P= W/T
W=F*D
and F=kgms^-2 (F=ma=Kg*ms^-2)
therefore
V=F*D/T and this divided by I
F*D/T gives Kgms^-2 * m * s^-1 ( the time at the denominator) = Kgm^2s^-3
and then current is A and since its a denominator in the equation then its A^-1

therefore, V= Kgm^2s^-3A^-1

Title: Re: physics base units
Post by: superduper2009 on May 16, 2010, 09:01:24 am

Thank you v. much

Title: Re: physics base units
Post by: [Spy] on May 16, 2010, 09:16:18 am

No Problem :)