IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: Recko on May 11, 2010, 08:16:53 am
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Hey Guys
I'm Going to start with myself first, please oct/nov 05, question 9 part iii
i've found out that tan x= gradient, where x is the angle between the line and the x-axis is that correct?
if so, then why do you find the difference between the two angles anyways?
thanks in advance
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Because you have to find the angle between the 2 lines
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hold i'll get you the post...I've answered this before
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https://studentforums.biz/index.php/topic,6531.120.html
Here
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THANK YOU SO MUCH! =D
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no problem :)
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I have another question
oct/nov 06
question 9 i) & ii)
:)
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or you could try vector method.
I use it and i find it easier, though some ppl might find it weird.
The tip is to use your gradient as a vector. Then u dot product them.
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can u show the dot product thing here
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oh..
so for example, if the first line's gradient is = 2. that would be 1i + 2j. And the second line's gradient is 3/2, that would be 2i + 3j.
(1i + 2j) . (2i + 3j) blah blah blah the dot product formula.
U could try it, but i think nid's one is standard mark scheme thing, so that way is more standard. Ull get the same answer thou.
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oh..
so for example, if the first line's gradient is = 2. that would be 1i + 2j. And the second line's gradient is 3/2, that would be 2i + 3j.
(1i + 2j) . (2i + 3j) blah blah blah the dot product formula.
U could try it, but i think nid's one is standard mark scheme thing, so that way is more standard. Ull get the same answer thou.
thanx got it ;) ;)
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Guys, i finished all papers,and i cracked every single question! and i know everything!
what do you think i should do now?
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Start P2
Jump for joy
Write to your President. He's a Nutter.
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hahaha start P2? i still didnt do the exam sir :P and no thanks ill pass :P
hahaha my president?
sir can you please help me out in oct/nov 06 question 9 i) and ii)
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What am i here for ? ;)
9)total surface area=200
10xy(the 2 sides) + 24x2(the 2 triangles)=200
10xy=200-24x2
y=200-24x2/ 10x
ii) V= 12x2y (area of cross-section into length) Area of cross section=area of triangle and length=y
now from the above eqn we know y=200-24x2/ 10x
substitute this in V
12x2(200-24x2/ 10x)
this gives 240x-28.8x3
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i get the sides part, but i dont understand the triangles one, and you dont take the upper side because its open right?
thanks! you rock ;)
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Area of the triangle is 1/2 bh
base is 8
half base is 4
drop a perpendicular on the base. you get 2 right angle triangles. Use Pythagoras rule to find the height.
h= )
=3
so area of the triangle= 1/2 X 8 X 3= 12cm2
since there are 2 it will be=2X12=24cm2
Yes you don't take the top cuz it's open..
lol...Thank You :P
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i thought it was going to be like that but then i saw it was only three marks i changed my mind haha :P
thanks again
good luck to you :)
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You're welcome. :)
Wish you the same :)
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by the nid404, did you finish all papers? because i almost finished every single thing and im just solving again and going through my silly mistakes( -.- ) lol
what you think i should do?
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here
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by the nid404, did you finish all papers? because i almost finished every single thing and im just solving again and going through my silly mistakes( -.- ) lol
what you think i should do?
I'm reading through the textbook and going through examples cause im done with papers too
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hey sir astarmathsandphysics do u have some wicked tough tough and extra tricky questions for AS level P1 maths that could really work the mind cos i even i have done all the papers thx ;D
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here
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didnt finish the papers :s,
thou P1 is really really simple :), all i want is that 75 hehe.
oh and theres thinking skills for me tmmr, wow bummer.