Post by: doubtigetastar on May 10, 2010, 01:58:18 pm
Post by: nid404 on May 10, 2010, 02:03:12 pm
c is the y-intercept. So, you get this first as +3
The equation of the given graph reduces to y=a sinbx +3
Functions of the form f(x) = a sin x are dilation of the curve sin x parallel to the y axis.
Now the normal graph of sin(x) lies between – 1 and + 1.
In the graph we have been given that the graph lies between + 9 and -3
So the graph has been dilated 6 times. Thus a = 6.
The equation of the given graph reduces to y = 6 sin(bx) + 3
Functions of the form f(x) = sin(bx) are dilation of the curve sinx parallel to the x – axis.
This means that the period of the graph is altered.
The graph of f(x) = sin(bx) will show b cycles in 2
period will be given by T=
T of the graph is
b=2
The equation of the given graph reduces to y = 6 sin(2x) + 3
Comparing with the graph of y = a sin(bx) + c we get a = 6, b = 2 and c = 3.
Post by: doubtigetastar on May 10, 2010, 02:26:28 pm
Post by: nid404 on May 10, 2010, 02:27:34 pm
Post by: highly_ambitious on May 11, 2010, 06:18:58 pm
Post by: nid404 on May 11, 2010, 06:43:05 pm