Post by: dlehddud on May 05, 2010, 09:49:23 am
i)Find the gradient of m of the line segment joining the points A and B with x-coordinates 0 and 1 respectively on the graph of y=
With this value of m, the line y=mx+c is drawn to meet the y-axis at C and intersect the graph of y=
ii)Find the value of c which makes the maximum value of lPQl equal to the value of the distance lACl
Relatively hard question.. even my teacher couldn't solve it.. but strangely the students could haha break a leg :D
Post by: ~ A.F ~ on May 05, 2010, 09:59:00 am
c= (0,1)
Post by: dlehddud on May 05, 2010, 10:01:24 am
m=e-1
c= (0,1)
m is right, but c is wrong.
if c was (0,1), then AC would be zero (on the graph, the C is capital not lower case. The question asks for the lower case c, or the y-intercept of the equation y=mx+c
Post by: ~ A.F ~ on May 05, 2010, 10:18:07 am
y= x(e-1) +1
x=0, y=1
Post by: dlehddud on May 05, 2010, 10:37:26 am
c must be 0,1
y= x(e-1) +1
x=0, y=1
yes, but y= x(e-1)+1 is not the equation of the form y=mx+c which will make lPQl equal lACl
Post by: astarmathsandphysics on May 05, 2010, 11:46:21 am
Post by: dlehddud on May 14, 2010, 10:56:55 am
I dont know if it is the right answer but is the right form.
fine.. answer is
now this is the challenging part XP why is the answer this? because it definitely is the answer.
Post by: dlehddud on May 14, 2010, 11:01:22 am