IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: Igcseboy on April 26, 2010, 04:29:58 pm
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Jan 2008 question 6 d....... m1 edexcel
helpppp!!!
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upload the paper
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http://www.srepapmaxeeeerf.org/A%20Level/Maths/Edexcel/2008%20Jan/6677_01_rms_20080306.pdf (http://www.srepapmaxeeeerf.org/A%20Level/Maths/Edexcel/2008%20Jan/6677_01_rms_20080306.pdf)
heres the link!!!!!
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same paper question 7 c
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Ohk..thanks..in 2 hrs
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this one as well jan 2009 question 5b i an ii
plzz try to be a bit more fast
thanxx
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the link is broken :-\
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no its f999
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nope
look at the attachment
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Everybody here tries as hard as they can to help. Please be patient cos the all have to study or work too
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asalamoalaikum...
i have an exam by 6 in the morning
plz help me wid these qns
Q5 b(2)
Q6 (a)
Q7 (b)
urgenttttttttttt!!! :)
Thanks
Jaza kALLAH khairan!
Allah Hafiz
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When I get up
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jan 08 question 6
a) (-5) ^2 + 8)^2 = 89 = under square toot = 9.43
b) draw the triangle first to understand and find the angle tanx = 8/5 so x = 57.99= 57.99+ 270 to find the bearing. draw the trinagle to understand it
c) r= r0 + vt
r = (7i-1oJ) + (-5i+8j)*3
r= -8i + 14J
r= r0 + vt
r0 = -8i + 14J because it is moving again from this point
-8i+14j + (ui+vj)*4 = 0 (as it returns to same position vector)
equal postion vector i is the same and j is the same so
-8i + 4ui = 0
u = 2
same you do for J (equal) so v = -3.5
d)
p.v. of P t secs after changing course = (–8i + 14j) + t(2i – 3.5j)
= 7i + …..
Hence total time = 10.5 s
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the wink over there should be 8 I don't know why is it appearing like that
as for the others they were pretty hard I didn't want to solve them again cz in the first time i messed up in the paper jan 09
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Done it. Will scan now
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here
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here