IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: Igcseboy on April 22, 2010, 12:34:03 pm
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I need urgent help i have my mocks on saturday and so i was practicing the past papers
please any1 help!!!
MAY 2005 Question 8 c
MAY 2006 11 d
JAN 2007 3
MAY 2007 5 and 11 c
JAN 2009 8 b (ii)
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Give me some time
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Is 2 hrs enough???
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MAY 2005 Question 8 c:
Area= 0.5 x base x height
base= OC = 7
Height= x-coordinate of P as its perpendicular to the base = 3
Therefore Area- 0.5 x base x height
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Is 2 hrs enough???
lol no i already posted the 1st question :)
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I always have difficulty downloading edexcel papers...
Thanks AF :)
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MAY 2006 11 d:
What's your problem with triangles lol :P ?
Anyways:
Area= 0.5 x base x height
height = RS = 2(50.5)
Base= PQ= (11+1)^2 1+ (8-2)^2 all square root
therefore area= 45 units of area
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I always have difficulty downloading edexcel papers...
Thanks AF :)
No prblm nid..But why is that? Tried FEP? :-\
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No prblm nid..But why is that? Tried FEP? :-\
Yup...the thing is it's not named properly...I get confused as to which paper it is...sometimes im lucky enough to get
thanks...you're doing a great job
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in may 2005 11 d how is RS the ht..
Ya i have prb. with area of triangles in C1 :D
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JAN 2007 3:
(a) All u've gotta do is to transform the y-coordinates 3 upwards....
Therefore, the x- asymptote doesnt change..
but the y-asymptote changes to +3 (0+3=3)
In other words, The whole graph shifts by +3 units upwards..x-coordinates dont change
(b) It crosses the x-axis when y=0:
(1/x)+3=0
(1/x)= -3
x= -1/3
It crosses the y-axis when x=0:
(1/0)+3 =y
It gives us math error, therefore it doesnt corss the y-axis
Therefore, only coordinates:
(-1/3, 0)
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in may 2005 11 d how is RS the ht..
Ya i have prb. with area of triangles in C1 :D
RS is the height as it already told you its perpendicular to the base....got it?
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RS is the height as it already told you its perpendicular to the base....got it?
oh yes!!!! so the ht.. will always be the one perpendicular to the base?????
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MAY 2007 5:
(a) We have to transofrmations..
1. Multiplying the whole function by 3-----> i.e. multiply the y-coordinates by 3-----> still no change in general shape of the curve..
2. +3 near x-----> i.e subtract 3 from x-coordinates ------> graph moves by 3 units to the left...
Asypmtotes:
y-asymptoe: 3x 0=0
x-asymptote: 0-3=-3
Finding coordinates:
Only with y-axis: put x=0:
therefore------> (0, 3/2)
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MAY 2005 Question 8 c:
Area= 0.5 x base x height
base= OC = 7
Height= x-coordinate of P as its perpendicular to the base = 3
Therefore Area- 0.5 x base x height
here it is not mentioned tht P is perpendicular???
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oh yes!!!! so the ht.. will always be the one perpendicular to the base?????
Of course!! Its a must!
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here it is not mentioned tht P is perpendicular???
Yes..but u have to use logic and common sense...the base is on the y-axis..Therefore ANY point with its x-coordinate will be perpendicular to it!
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Yes..but u have to use logic and common sense...the base is on the y-axis..Therefore ANY point with its x-coordinate will be perpendicular to it!
oh ya Thanks :)
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JAN 2009 8 b (ii) :
As i said before:
y-intersections-----> put x=0:
(1)^2 (2-0)= 2 --------> (0,2)
x-intersections-----> put y=0:
x=-1, 2 --------) (-1,0) (-1,0) (2,0)
Then draw a cubic graph...since coefficient of x^3 <0 (when u expand the function), it will take the negative parabola form..
THATS IT! lol :P
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JAN 2009 10 d
JAN 2006 9
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Sorry..I'm out now..When I go home :-\
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ok..
Thanx Aloot