IGCSE/GCSE/O & A Level/IB/University Student Forum

Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: joel on April 20, 2010, 05:16:46 pm

Title: Statastics 1 CIE Dout
Post by: joel on April 20, 2010, 05:16:46 pm

Giving a brief explanation of your method, calculate the number of different ways in which the letters of the word TRIANGLES can be arranged if no two vowels may come together.

The answer is 151200.

This Question has been taken from Cambridge Advanced Level Mathematics Statistics 1 - Steve Dobbs and Jane Miller
Chapter 5 - Permutations and Combinations  miscellaneous exercise 5 question 8.

How do arrive at this answer?

Title: Re: Statastics 1 CIE Dout
Post by: sweetie on April 20, 2010, 06:10:12 pm

6! * 7P3

6! - no. of wayz the consonants cud be arranged

7P3 - no. of wayz the 3 vowels cud be arranged

Title: Re: Statastics 1 CIE Dout
Post by: joel on April 20, 2010, 06:12:55 pm

Thanks a lot

Title: Re: Statastics 1 CIE Dout
Post by: sweetie on April 20, 2010, 06:15:55 pm

ur welcum ;D