IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => University => Topic started by: SGVaibhav on April 19, 2010, 12:34:00 pm
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This came in applied mechanics - equilibirum of a particle...
I got equations, and i dont know how to solve them ??
1- 2500 = TAC cos (T)
2- 500 = TAC sin (T)
for those who are confused with TAC, take it as a single variable x......
i dont know how to solve such equations...
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This came in applied mechanics - equilibirum of a particle...
I got equations, and i dont know how to solve them ??
1- 2500 = TAC cos (T)
2- 500 = TAC sin (T)
for those who are confused with TAC, take it as a single variable x......
i dont know how to solve such equations...
No worries..You cannt solve with simultaneous..it will take a long time..Divide both equations by each other...sin/cos=tan
Therefore:
tan (T)=0.2...Then use the triangle method to find the values of sin and cos..
got that?
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This came in applied mechanics - equilibirum of a particle...
I got equations, and i dont know how to solve them ??
1- 2500 = TAC cos (T)
2- 500 = TAC sin (T)
for those who are confused with TAC, take it as a single variable x......
i dont know how to solve such equations...
Tac =500/sinT
Substitute
u will get 5sint=cost
squre all the equ. ( 5sint=cost )^2
25sin^2t=cos^2t
25sin^2t= 1-sin^2t
26sin^2t=1
sin^2t=1/26
take the squre root
sint= (1/26)^0.5
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Tac =500/sinT
Substitute
u will get 5sint=cost
squre all the equ. ( 5sint=cost )^2
25sin^2t=cos^2t
25sin^2t= 1-sin^2t
26sin^2t=1
sin^2t=1/26
take the squre root
sint= (1/26)^0.5
As i said..it will take such a long time..:P mine is easier ;D
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Yes A.F's is way easier.....saves time...it's P1 stuff
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As i said..it will take such a long time..:P mine is easier ;D
ya i know ;)
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@T.Q... thanks i understood :D
but at times, it can get more complex...
so
@A.F .. how did u do it?
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@T.Q... thanks i understood :D
but at times, it can get more complex...
so
@A.F .. how did u do it?
It's P1 stuff...we do it in A level
divide the equations...so u get
500/2500 = TAC sin (T)/ TAC cos (T)
sin(T)/cos(T)=Tan (T)
Tan(T)=0.2
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This came in applied mechanics - equilibirum of a particle...
I got equations, and i dont know how to solve them ??
1- 2500 = TAC cos (T)
2- 500 = TAC sin (T)
for those who are confused with TAC, take it as a single variable x......
i dont know how to solve such equations...
Divide both equations by each other:
Tsin(T)/Tcos(T)=500/2500...The tension cancels out..
sin/cos=tan (T)
500/2500=0.2
how about now?
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oooooppsss..sory nid..posted in the same time ;D ;D
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oh..
we divide :P equations..
now i understood :D :D :D
thanks everyone =)
lol
i got new reply posted twice :P