IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: 7ooD on March 28, 2010, 02:13:22 pm
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write the following in simplest form involving only one trigonometric function
tanA/(sec^2A)-2
i tried to solve it as following
(sec^2A)=tan^2A+1
tan^2A+1-2
tan^2A-1
-(-tan^2+1)
tanA/-(-tan^2+1)
2tanA/-(-tan^2+1)
-2(1/2tan2A)
-tan2A
in the answers it says -1/2tan2a not -tan2a as i solved above wat did i do wrong
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there u go
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lol my mind stopped i couldn't complete the rest thx dude
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here to help u all