IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Sciences => Topic started by: nid404 on March 25, 2010, 05:51:59 pm
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A parallel beam of light of wavelength 450 nm falls normally on a diffraction grating which has 300 lines/mm
What is the total number of transmitted maxima?
Ans:15
Please explain it
Thanks in advance...This is really very urgent
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2 hours
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Ok.. :(
Somebody else could give it a try...please :'(....I'm not too good at waves!
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sin x=nw/d<1
300 line/mm so d=0.001/300=3.33*10^-6
n<d/w=3.33*10^-6/(450*10^-9)=7.4 so n=7
that means 7 fringes on either side +1 in the middle =15 fringes
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Ohhhh......either side of the central maxima!! slipped outta my mind...
luckily i didn't have a question on this
Thanks sir