IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: osmosis on February 18, 2010, 03:14:56 pm
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can anyone help me how to find the two consecutive integers for question no.2 OCT/NOV 2009 pure math 3 paper??? ???
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do we need to just substitute any integer??? or is there any other way to get x=3 and x=4???
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Will answer when I get up
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3^(x+2)=3^x+3^2
3^(x+2)-3^x=3^2
3^x(3^2-1)=3^2
3^x=3^2/(3^2-1)
xln3=ln(3^2/(3^2-1))
x=ln(3^2/(3^2-1)))/ln3
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owh...that is for paper 31.... mine is paper 32....about finding the two consecutive integers on numerical solution topic.....that's where I got problem in finding the integer...can you help me with that one? :)
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How did I miss that? When I get home.
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Trial and error. The root is between 3 an 4
f(3)<0 f(4)>0
so between 3 and 4 there is a sign change and a root.
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ok....thank you so much! :)