IGCSE/GCSE/O & A Level/IB/University Student Forum

Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: Light on February 06, 2010, 02:01:33 pm

Title: integration
Post by: Light on February 06, 2010, 02:01:33 pm
how to integrate by recognition: (7x^2)(x^3 +1)^5 dx ?
Title: Re: integration
Post by: astarmathsandphysics on February 06, 2010, 02:22:47 pm
Multiply the bracket out then integrate term by term using \int Ax^n dx = \frac{Ax^{n+1}}{n+1}
Title: Re: integration
Post by: Light on February 06, 2010, 02:30:02 pm
but the answer is in form of factorised with power.is there any shorter way?power 5 need long way of expanding.==
Title: Re: integration
Post by: astarmathsandphysics on February 06, 2010, 02:34:49 pm
I didn't see the power cos I was blinded by q80's link. Better then integration by substition

u=x^3+1
u=x^3 so du=3x^2 dx
\int 7x^2(x^3+1)^5dx=\int 7/3 u*u^5du=\int 7/3 u^6du = 7/18 u^6 =7/18 (x^3+1)^6 +C
Title: Re: integration
Post by: Light on February 06, 2010, 02:35:48 pm
but question says integration  by recognition.
Title: Re: integration
Post by: astarmathsandphysics on February 06, 2010, 03:02:33 pm
I am surprised. Manipulation involved. See my answer above