IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: XFlufferzX on January 17, 2010, 11:02:30 am
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Da paper is attached
I stucked in question 3 b ii)
b ii)
= [ 2 ln 5 - 3 ln 3 + ln5] - [ 2n ln - 3l + ln3]
= " 3 ln 5 - 4 ln 3 " <---- I didnt know how to get this by subtracting [ 2 ln 5 - 3 ln 3 + ln5] from [ 2n ln - 3l + ln3]
can someone explain it fer meh!
thankss alot ;D
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[ 2 ln 5 - 3 ln 3 + ln5] - [ 2 ln1 - 3ln1 + ln3]
=[3ln5-3ln3]-[0-0+ln3] since ln1=0
=3ln5-3ln3-ln3=3ln5-4ln3=ln(5^3/3^4)=ln(125/81}
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[ 2 ln 5 - 3 ln 3 + ln5] - [ 2 ln1 - 3ln1 + ln3]
=[3ln5-3ln3]-[0-0+ln3] since ln1=0
=3ln5-3ln3-ln3=3ln5-4ln3=ln(5^3/3^4)=ln(125/81}
Thankss!! :D