IGCSE/GCSE/O & A Level/IB/University Student Forum

Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: XFlufferzX on January 09, 2010, 04:31:02 pm

Title: M1 question!!
Post by: XFlufferzX on January 09, 2010, 04:31:02 pm: I need help with part d and e please
THANKS! :D
Title: Re: M1 question!!
Post by: astarmathsandphysics on January 09, 2010, 04:56:27 pm: will try it now
Title: Re: M1 question!!
Post by: XFlufferzX on January 09, 2010, 05:03:54 pm: Thanksssss alot!!!
Title: Re: M1 question!!
Post by: astarmathsandphysics on January 09, 2010, 08:39:28 pm: a)speed= $sqrt((-2.5)^2+6^2)=6.5$
b) $360-tan^{-1} (2.5/6) =337 degrees$
c)ship is at 16i+5j+t(-2.5i+6j)
when t=3 ship is at 16i+5j+3(-2.5i+6j)=8.5i+23j
d)at 1400 ship is at 16i+5j+2(-2.5i+6j)=11i+17j and then starts to move north with v=5j
position of ship t hours after 1200 is 11i+17j+5(t-2)j
e) due east mean the j components are the same
ie 23=17+5(t-2)
5(t-2)=6
t-2=1.2 hours
t=3.2 hours=3 hours 12 mins after 12 ie 1512
Title: Re: M1 question!!
Post by: XFlufferzX on January 09, 2010, 08:54:43 pm: Quote
a)speed=sqrt((-2.5)^2+6^2)=6.5
b)360-tan^{-1} (2.5/6) =337 degrees
c)ship is at 16i+5j+t(-2.5i+6j)
when t=3 ship is at 16i+5j+3(-2.5i+6j)=8.5i+23j
d)at 1400 ship is at 16i+5j+2(-2.5i+6j)=11i+17j and then starts to move north with v=5j
position of ship t hours after 1200 is 11i+17j+5(t-2)j
e) due east mean the j components are the same
ie 23=17+5(t-2)
5(t-2)=6
t-2=1.2 hours
t=3.2 hours=3 hours 12 mins after 12 ie 1512

THANK YOU SO MUCH!!!!!!!!!!!!!!!! :D