IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: T.Q on December 20, 2009, 04:58:25 pm
-
A curve C has equation
y=3sin2x+4cos2x,
The point A(0, 4) lies on C.
(a) Find an equation of the normal to the curve C at A
when i defferintiate i got this dy/dx= 6cos2x - 8sin2x
my problem was when i subsituted the x=0 i had the wrong value of the gradient
in the MS m=6
show your working
-
A curve C has equation
y=3sin2x+4cos2x,
The point A(0, 4) lies on C.
(a) Find an equation of the normal to the curve C at A
show your working
dy/dx=6cos2x-8sin2x so gradient m=6cos(2*0)-8sin(2*0)=6 and m for normal is -1/6
y-y1=m(x-x1)
y-4=-1/6(x-0) so y=-x/6+4
-
dy/dx=6cos2x-8sin2x so gradient m=6cos(2*0)-8sin(2*0)=6 and m for normal is -1/6
y-y1=m(x-x1)
y-4=-1/6(x-0) so y=-x/6+4
thanx now i got it