IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: sweetest angel on December 16, 2009, 05:54:15 am
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june 2009 Q2 b) (attached)
this is the answer
R = (i - 3j) + (pi + 2pj) = (1 + p)i + (-3 + 2p)j
R is parallel to i ? (-3 + 2p) = 0
? p = 3/2
but i dnt get it. if R is parallel to i then the value of i=0 not j=0 ?
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june 2009 Q2 b) (attached)
this is the answer
R = (i - 3j) + (pi + 2pj) = (1 + p)i + (-3 + 2p)j
R is parallel to i ? (-3 + 2p) = 0
? p = 3/2
but i dnt get it. if R is parallel to i then the value of i=0 not j=0 ?
because i is a straight horizantal line so it will have a zero j
and because R is parallel to i ,then R will have the value of j equal to zero
thats why they took the j value equal to zero
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ohhhhh...but we dnt knw if it passes through j or not so maybe it has a j value ???
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ohhhhh...but we dnt knw if it passes through j or not so maybe it has a j value ???
consider the whole set up on the 
consider an arbitrary vector and the unit vector 
We assume both vectors are parallel.
Lets assume the arbitrary vector is
+ 
Gradient of
= Gradient of the other vector

Thus if an arbitrary vector and
are parallel, the co-effecient of j for the arbitrary vector has to equal 0.
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ohhhhh...but we dnt knw if it passes through j or not so maybe it has a j value ???
a vector (2D) has two components; i and j which define its direction.
It cannot "PASS" through j. its a component. It can pass through a point.