IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: helllife on November 21, 2009, 10:10:31 am
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question is ...
express this in terms of ratios of acute angles
cos(165)
i know this is simple one...but i just didnt understand how to find it...
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u know the rule cosx =-cos(180-x)
so cos165=-cos(180-65)=-cos15
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oh really? is there such a rules like this? can u please give more rule? like about sin?
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It is cosx=-cos(180-x)
Sinx=Sin(180-x)
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sinx=sin(180-x)
cosx=-cos(180-x)
tanx=-tan(180-x)
sin(90-x)=cosx
cos(90-x)=sinx
tan(90-x)=1/tanx
sin(-x)=-sinx
cos(-x)=cosx
tan(-x)=-tanx
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thank you very much!!! :)
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and also
sin(x+360)=sinx
cos(x+360)=cosx
tan(x+180)=tanx
there are many more but ive forgotten them
and ur welcome ;)
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hey what about
sin(180+x), cos(180+x), tan(180+x)??
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Will post when i get home. There are some useful formulae.
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hey what about
sin(180+x), cos(180+x), tan(180+x)??
oh sory..........tan(180+x)=tanx
and sin(180+x)=-sinx
and cos(180+x)=-cosx
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Ok but Sin(180+x)=-Sinx
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thank u very much!! i really appreciated it! :)