IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: SGVaibhav on November 10, 2009, 02:57:51 pm
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[WARNING: VERY ANNOYING STUFF INSIDE ---> ENTER AT UR OWN RISK]
need to explain to full class, that how do we derive
the derivatives of arcsin, arccos, arctan, arcsec, (need to explain to full class, that how do we derive and get this values).
need to submit with 4-5 pages of handouts.
if anyone can help in any way, please do,
right now, i am reading it in wiki, (but am pretty confused ???) (lol :D still maths is fun :D)
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y dont u post this in the a level thread instead?
and inverse trig derivatives...dont know how to do them.......sory.....i bet astar knows
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Yeah ill move it there :)
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Gimme a moment, I'll give you an example and you can try proving it on other inverse trigo functions :) Will post it after this.
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well, i was reading on wiki, how to derive the inverse sine function.
and i came across this
they have reached till here
http://upload.wikimedia.org/math/a/b/3/ab3d5da927e35f4370bb0b9c0b483189.png
and now they wrote this thing
http://upload.wikimedia.org/math/8/8/a/88aedc93821b18cfc22c28cf970cd133.png
from where does this come ???
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Is this what you need?
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reading
looks effective so far
excited
will try that on cos and will tell if it works
Be right back reading :D
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how do we know that we have to find the adjacent side ???
and how do we get (root)1-x^2, that is confusing me
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im not getting it :'(
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'Cause sin y = x which from that you know the opposite side is x and the hypotenuse is 1. What about the adjacent? Imagine a right-angled triangle with one of its acute angles as y.
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how is the hyp 1
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sin y = x meaning sin y = x/1 haha. And sin = opposite/hyp
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lol thanks,
let me try to continue
so stupid >:(
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Haha, no prob :D You might have a problem with sec and cosec though, but do try it xD
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lool
i was typing, BRAINS r like parachutes, plz open
and was going to type a doubt.
but got the answer
im convinced how do i get the answer, but im not sure if this method will be enough to convince others. im practicing how to convince others :D ;D ;)
thanks for help :D
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It will be, trust me :D By the way, you wanna show how you showed your working? Maybe you can try include a figure of a right-angled triangle to explain the specific lengths :)
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found out, how to explain
the only confusing part to explain is the adjacent part, so i will find out adj in the beginning, when i draw a triangle.
now going to COS
hope its easy :D
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found out, how to explain
the only confusing part to explain is the adjacent part, so i will find out adj in the beginning, when i draw a triangle.
now going to COS
hope its easy :D
Haha, I guess you can do it :D you can do it like let's say you draw a triangle ABC. Angle ABC = 90. Put angle CAB as y then you can illustrate :)
And be careful on the cosine part. Remember that its derivative is a negative sine. :)
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DONE xD
first try, did not use the net also, no helps
wow :D,
now i got 2 more functions remaining
tan inverse and sec inverse
tan should not be a big prob
sec looks scary :o ::) O0
going with Tan now
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Haha! You can do it! :D Once you get the hang of it you can do it :) You wanna try the following?
Find the derivative of y = sin^-1 3x^2 :D
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crap crap crap
im stuck with sec, i know how to do it.
but i hope other classmates understand, because im not good at EXPLAINING algebra, because i do it mentally, specially stuff such as sec y = 1 / cos y
so that is = 1 / (adj / hyp)
crap boring to explain :-\
let me try to finish it now :)
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got the answer
is the answer 1 / (1 + x^2) ???
lol i dont know.
w8 checking book
right :D :D :D
now the scariest part ever
the don of DONS sec filled with modulus
doing sec inverse now
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crap crap crap
im stuck with sec, i know how to do it.
but i hope other classmates understand, because im not good at EXPLAINING algebra, because i do it mentally, specially stuff such as sec y = 1 / cos y
so that is = 1 / (adj / hyp)
crap boring to explain :-\
let me try to finish it now :)
Haha, you want me to try do it for you? :)
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let me try
practice
trying
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let me try
practice
trying
Haha! Okay, lemme know if you're stuck xD
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awww
reached
dy/dx = 1 / (x . root (x^2 - 1) )
lol hope u got that part
now thinking how to proceed.
if i multiply the whole thing by x^2 - 1 , then the root still stays.
if i multiply the whole thing by the root of x^2 ....., then the root comes above
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w8
i checked my book now, and this is the final answer,
except the modulus part exists for x.
how does the modulus come ???
need help now
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Hmm I saw that too. Lemme think about the modulus part :) Gimme a while.
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w8
i checked my book now, and this is the final answer,
except the modulus part exists for x.
how does the modulus come ???
need help now
Hmmm... I think this site can help :)
http://archives.math.utk.edu/visual.calculus/3/inverse_trig.1/5.html
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So, do you understand it now? xD
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sorry i was away,
trying it now
this method is little different and making it little confusing
trying now
is there any such rule that sec x tan x should be > 0 or something
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ok got that part
confusion confusion confusion
in that site....
when they find the derivative of sec inverse for the range (pi/2) till pi.
they get a negative sign in the denomintor before the square root
how is that now
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ok got that part
confusion confusion confusion
in that site....
when they find the derivative of sec inverse for the range (pi/2) till pi.
they get a negative sign in the denomintor before the square root
how is that now
'Cause for cos x where pi/2 < x < pi, it is negative haha.
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this was truly confusing >:( :(
it will be very hard to explain.
but why do we need to care to put modulus
if there is no modulus, then the answer comes negatives (LET IT STAY NEGATIVE IF IT IS NEGATIVE >:()
annoying :-\
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yep one more thing
when sec goes negative, tan also goes negative
so negative x negative = positive
im going off pc now probably
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I differenthated them all but i posted in the ib board
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nice
lol i edited the main page
haha
warning
thanks for help :D
will never forget this now.
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yep one more thing
when sec goes negative, tan also goes negative
so negative x negative = positive
im going off pc now probably
Yep yep! Haha that explains the modulus :) Anyway, all the best for the presentation xD
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loooooooool
haha, that -ve x -ve = +ve was a doubt
but when u said it explains the modulus, i realised that the doubt is the solution ???
cya tom
thanks for help
bye
Take care
goodnight
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loooooooool
haha, that -ve x -ve = +ve was a doubt
but when u said it explains the modulus, i realised that the doubt is the solution ???
cya tom
thanks for help
bye
Take care
goodnight
Haha! Take care and goodnight :)
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https://studentforums.biz/index.php/topic,4796.msg150350.html#msg150350
inverse trig functions are differentiated here.
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:(
sir wanted it written in a paper, while i thought it had to be explained to the full class.
now i will open word 2007, write down steps, print it and give it to him
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:(
sir wanted it written in a paper, while i thought it had to be explained to the full class.
now i will open word 2007, write down steps, print it and give it to him
Lol. But did you get everything now? :) I guess you've done it all :D
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yeah i got it