IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: spiderman on October 16, 2009, 03:38:15 am
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Hey guys,
pls can ull help me out with this question......
a) Express 9x^2+12x+7 in the form (ax+b)^2 + c where a,b and c are constants whose values are to be found.
b) Find the set of values taken by 1/(9x^2+12x+7) for real values of x.
Someone pls helppppp. ???
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a) is completing the square method
so it is (3x+2)2+3
b) 0<f(x)<=1/3
this is becuz no value of f(x) can be less than zero....since a negative x will be squared to give a positive value...
the greatest value of f(x) would be when denominator is least...this will be possible only when denominator is 3 and bracket is 0. hence 1/3
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Thanks a lot
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Thanks a lot
ur welcome.