IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => IB => Sciences => Topic started by: Tutu_93 on October 05, 2009, 07:55:27 pm
-
I am stuck in a question in chemistry
A 1.39 g sample of hydrated copper (2) sulfate ( cuso4.xH2O)is heated until all the water of hydration is driven off.The anhydrous salt has a mass of 0.89 g . determine the formula of the hydrate ??
-
First use the mass of the copper sulfate after all the water is gone to determine the moles of CuSO4
0.89/159.5 = 0.0055
The mass loss on heating can be used to determine the moles of water lost:
(1.39 - 0.89)/[(2 x 1) + 16] = 0.0278
Now determine the ratio of water to CuSO4
0.0278/0.0055 ~ 5
----
(because its moles of water to moles of copper sulfate ratio)
-
Yaa i knw ..
The actual answer is 5
-
i edited it..check again
-
:D:D:D:D :D thhhhnnnnnk u
-
okay.