IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => University => Topic started by: astarmathsandphysics on October 06, 2008, 11:07:33 am
-
Post your Degree questions here to get the answers back asap from someone with 3 maths/physics degrees.
-
Hi, needed help on my coursework, would be great if you could help
Thankyou
-
When is your deadline?
-
Look tomorrow.
-
its due 9th march, when do u think you will be able to look at it?
-
you haven't uploaded the work yet, when will you be able to?
-
Spank me roma, give me a good slap around the head because I havent uploaded your coursework yet. Fact is, now on Friday 945pm I am in no condtion to add 2 numbers together.
-
will you be able to do it today then?
-
Yes. Am free this afternoon from 3 o'clock
-
How do you even get all this time to do it all ?? Plz tell me ur secret, caus I love to work.
-
Be obsessed.
-
ok, how about now then?
-
finished it. Got to go out now but back in 2 hours. Will post it then.
-
Trouble trouble trouble. My scanner has saved it as 4x128MB file which means I can't post it on the forum or email it. Suggest I fax it or upload it to www.courseworkbank.info
-
where can i find it on that website?
-
Will pm you
-
Another satisfied customer. My scanner saved all the scans as a 128MB file and I had still to learn to use Latex. Luckily she lives in London so I met her at a train station on my way to a student and gave her a brown envelope.
-
Hello, me again! I've been a set a coursework but i will be tested on it. So i have to learn the method used in each question and i will have a test on it which will require me to use the same methods on the coursework. I was hoping you could have a look at it for me, so that i know im learning the right stuff
Thankz
-
Yes he it is posted here. Cant tell now am on phone
-
have you looked at it yet?
-
Dont i tell you make a nuisance of yourself? Am asleep.
-
Can you PLEASE help me then?
-
Hey, i needed some help on this question.
Prove p = 0.08512 B = 0.01881 A = 0.03119 simultaneously,
20 =1/(A + B)
23 =1/(A + Be^-5p)
25.5 =1/(A + Be^-10p)
-
2 hours
-
Any luck?
-
Hi my exam's in 12 hours, and I just don't get statistics. Please help with this question,
Consider the 10 data items x1, x2, ... x10. Given that Sum(xi) = 1341 and the standard deviation is 6.9, find the value of the mean .
The answer is:
6.92 = 1341/10 - mean2
and then the answer works out to be +/- 9.3 .
I get the method, I just don't get why they divided by 10 ?
-
There must be more to the question than that. Cabn you post the question?
-
I'm sure that's the whole question. I don't know what you mean by post it
-
This is an old topic . Can you you ropost to make it current?
-
Hey, i needed some help on this question.
Prove p = 0.08512 B = 0.01881 A = 0.03119 simultaneously,
20 =1/(A + B)
23 =1/(A + Be^-5p)
25.5 =1/(A + Be^-10p)
1)20 =1/(A + B)
2)23 =1/(A + Be^-5p)
3)25.5 =1/(A + Be^-10p)
Turn everything upside down
1/20 =(A + B)
1/23 =(A + Be^-5p)
1/25.5 =(A + Be^-10p)
top take away next onw gives B-Be^-5p=3/460 (4) and top take the third gives 5.5/510=B-Be^-10p Divide these 2 equtions by each other to give
(1-e^-5p)/(1-e^-10p)=0.604
sub x=e^-5p to give(1-x)/(1-x2)=0.604
so 1-x=0.604-0.604x2
so0.604x2-0.604x+0.396=0 Solve this and sub into 4 to find B then into 1 to find A
-
Hi my exam's in 12 hours, and I just don't get statistics. Please help with this question,
Consider the 10 data items x1, x2, ... x10. Given that Sum(xi) = 1341 and the standard deviation is 6.9, find the value of the mean .
The answer is:
6.92 = 1341/10 - mean2
and then the answer works out to be +/- 9.3 .
I get the method, I just don't get why they divided by 10 ?
Did you mean Sum(xi2)?
-
It doesn't work
-
what doesnt work?
-
Can anyone help me with this coursework.. I can't do q1 and question 2..... they are quite difficult...
thanks in advance
-
I will do it tomorrow morning.
-
thank you very much but can u plz posted it b4 12pm as i have to hand it in at 2 pm
-
I noticed that.
-
q3 needs software
-
thanks man... it did help with some of the confusion that i had
-
No probs
-
I asked a coursework company how much they would charge to do it. They said £180.