IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => IGCSE/ GCSE => Math => Topic started by: godfather93 on May 18, 2009, 11:21:34 am
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someone please explain question Q6) b)ii)?
I'm getting the wrong answer.
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Am not at home. Can someone else try
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someone else please!!
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i solved it. thread closed.
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okk..heres how u do it..
---------------RULE---------------------------------------------------
if class width = n * standard width, then, height = frequency/n
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first lets find the standard width...the height given = 11.5, its frequency is 115
therefore 11.5 = 115/n...=> n = 10
class width = 10 * standard width
2 = 10 * standard width
therefore standard width = 0.2
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now use this formula with standard width 0.2 to calculate the heights..
height = fequency * (standard width/classwidth)
1st - h = 35 * 0.2/10 = 0.7
2nd - 11.5 (given)
3rd - h = 26 * 0.2/2 = 2.6
4th - h = 24 * 0.2/6 = 0.8
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chk the markscheme for verification
good luck
byee
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okk...
good luck
byee
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thanks but i already solved it!
But thank you for your response!!! ;D ;D ;D ;D
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thank you!!!
Hopefully the exam will be good.
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ok let me explain...
first things first... u should know this FREQUENCY = HEIGHT X CLASS WIDTH, ok?
lets take the given example...
freq=115
class width=2
with the help of the formula, height= 115/2
=57.5
now the height (freq. density) SHOULD equal 57.5, but it doesnt..
it equals 11.5 cm..
now u will have to find the "FACTOR'' by which the height is reduced..
11/57.5 which equals 0.2, ok?
now find the supposed height of the other column..
(example..3rd column...)
height = 26/2 = 13...
now multiply 13 into the factor...
13*0.2 = 2.6!
there you go...
same thing with other columns....
if u dont get me, please notify,, i will try again ;D
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aww.. u just got it!
aneways..
i tried!! :)