IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Math => Topic started by: ashwinkandel on September 29, 2011, 03:32:56 pm
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Find the range of value of c, given that, for all values of x, x^2+5x+c>2
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c>33/4
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Can you show me the process?? how did u take out the answer
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Complet the squuare
x^2+5x+c>2
(x+2.5)^2-2.5^2+c>2
(x+2.5)^2-2.5^2+c-2>0
(x+2.5)^2 is a square number so must be greater than zero, so
-2.5^2+c-2>0 so c>2.5^2+2=8.25
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I am little bit confused with the last steps of the solution:
(x+2.5)^2 is a square number so must be greater than zero, so
-2.5^2+c-2>0 so c>2.5^2+2=8.25
I accept that (x+2.5)^2 is always greater than zero, then how can we say that -2.5^2+c-2 is also greater than zero?
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Can you also give a glance to this question: (http://i53.tinypic.com/16gk02t.png)
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Do you mean the question in black written in the black rectangle?
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Because if (x+2.5)^2>0 sub (x+2.5)^2=00 into (x+2.5)^2-6.25+2-2>0 then solve for c
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Thanks for clarification and yes, i mean the question in the black rectangle
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I can't read it.
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Right click the image and click view image or just go to http://i53.tinypic.com/16gk02t.png (http://i53.tinypic.com/16gk02t.png)
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A is 3 b is 2
Is there a diagram or min or max value of the function
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Max. Value of the function is given in the next part and diagram is asked to be drawn. I am still confused how you took out the value of a as 3.