IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => GCE AS & A2 Level => Sciences => Topic started by: missbeautiful789 on October 24, 2010, 09:49:34 am
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M/j 06 5(c)
Please could someone help me with this question, im not sure which approach to use. Much appreciated ;D
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I take it that you found the solution to part (b)
Work done by spring = 1/2 k ( x22 - x12)
c) You should find out the gain in strain energy of spring using the equation above. But you need to convert k in Nm-1 first. Hence k = 1600Nm-1
Gain in energy strain energy for both springs = 1/2(1600)(0.062 - 0.0452) + 1/2(1600)(0.032 - 0.0452) = 0.36 J
Strain energy gets converted into kinetic energy of trolley.
K.E = 1/2mv2 = 0.36
Taking m as 0.85kg ----> V = 0.92 ms-1
Hope it helps :)
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I used the formula from b.
my problem is:
I found that the work don to the right is 1.26J
And the work done to the left is -0.9J
so shouldn't the total work done on the mass be 1.26-(-0.9) to the right
so instead of 0.36, why isn't it 2.16J
(http://i52.tinypic.com/8y5g5u.jpg)
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I used the formula from b.
my problem is:
I found that the work don to the right is 1.26J
And the work done to the left is -0.9J
so shouldn't the total work done on the mass be 1.26-(-0.9) to the right
so instead of 0.36, why isn't it 2.16J
(http://i52.tinypic.com/8y5g5u.jpg)
Hehe.........my dear missbeautiful789
Energy is a scalar quantity. So it cannot be negative ;)
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Doh.. :o
thats what you get for blindly following formulas
+Rep DK
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Doh.. :o
thats what you get for blindly following formulas
+Rep DK
Hahahaha..........guess you are right :D
You should be glad you made the mistake here and not in exams ;)