IGCSE/GCSE/O & A Level/IB/University Student Forum
Qualification => Subject Doubts => IGCSE/ GCSE => Math => Topic started by: Haaks18 on October 22, 2010, 11:09:49 pm
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The sum of three numbers is 66. The second number is twice the first and six less than the third. Find the numbers
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first no = x
second no = 2x
third number = 2x +6
their sum is 66 so:
x + 2x + 2x + 6 = 66
5x = 60
x = 12
first no = 12
second no = 2 x 12 = 24
third no = 24 + 6 = 30
(:
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first no = x
second no = 2x
third number = 2x +6
their sum is 66 so:
x + 2x + 2x + 6 = 66
5x = 60
x = 12
first no = 12
second no = 2 x 12 = 24
third no = 24 + 6 = 30
(:
Yeah!! 8)